Consider the following reaction in a closed system: H2(g) + I2(g) → 2HI(g) Which of the following will decrease the rate of the forward reaction?
add some H2 remove some HI increase the volume increase the temperature
I like it's B @aaronq @brala00 @ganeshie8 @phi @ikram002p @waterineyes
B is : Remove some HI ?? Are you sure HI is there??
HI is your Output, if you remove that, that means you are collecting HI in your pockets.. :P
And that way, Rate of Forward reaction will remain same.. :)
Check if your option B is correctly written there, Is it \(HI\) or \(H_2\)??
It's definately Hl
I think its an L tho not an i
And what is Hl if it is l there??
I can't find it on the periodic table maybe it's Hydrogen and Iodine?
Yes, it is Hydrogen and Iodine.. I is for i, not L.. Compound name is : Hydrogen Iodide (HI)
Okay so we decided B is wrong, which makes me think A is also wrong
Increasing the volume of what??
of the solution I believe
I think it is like C..
Yay! we were right!
Good..!!
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