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Chemistry 15 Online
OpenStudy (anonymous):

Consider the following reaction in a closed system: H2(g) + I2(g) → 2HI(g) Which of the following will decrease the rate of the forward reaction?

OpenStudy (anonymous):

add some H2 remove some HI increase the volume increase the temperature

OpenStudy (anonymous):

I like it's B @aaronq @brala00 @ganeshie8 @phi @ikram002p @waterineyes

OpenStudy (anonymous):

B is : Remove some HI ?? Are you sure HI is there??

OpenStudy (anonymous):

HI is your Output, if you remove that, that means you are collecting HI in your pockets.. :P

OpenStudy (anonymous):

And that way, Rate of Forward reaction will remain same.. :)

OpenStudy (anonymous):

Check if your option B is correctly written there, Is it \(HI\) or \(H_2\)??

OpenStudy (anonymous):

It's definately Hl

OpenStudy (anonymous):

I think its an L tho not an i

OpenStudy (anonymous):

And what is Hl if it is l there??

OpenStudy (anonymous):

I can't find it on the periodic table maybe it's Hydrogen and Iodine?

OpenStudy (anonymous):

Yes, it is Hydrogen and Iodine.. I is for i, not L.. Compound name is : Hydrogen Iodide (HI)

OpenStudy (anonymous):

Okay so we decided B is wrong, which makes me think A is also wrong

OpenStudy (anonymous):

Increasing the volume of what??

OpenStudy (anonymous):

of the solution I believe

OpenStudy (anonymous):

I think it is like C..

OpenStudy (anonymous):

Yay! we were right!

OpenStudy (anonymous):

Good..!!

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