How can i put y=7 into slope-intercept form?
@aum
The line \(y=7\) is equal to 0. thus, any "x" multiplied to "0" equals 0 and the term drops off the slope intercept form..
y = 7 is the equation of a horizontal line parallel to the x-axis. The slope is zero. Threfore, in y = mx + b, m = 0 and so y = b. Here y = 7.
so there is no way to answer this? what if it was x=7?
Then there's still no possible slope..
For the first one: y = 0*x + 7 is the slope-intercept form of y = 7.
It is not possible to put x = 7 in slope intercept form because x = 7 is a vertical line and therefore the slope is infinity or undefined.
ok, i see! so because there is no m, it screws everything up. so slope is 0 and the y intercept is 7
yes, for the first one.
ok, what about for x=-6? (sorry, i just started algebra 2 today)
same answer as the previous question for x = 7. It is not possible to put x = -6 in slope intercept form because x = -6 is a vertical line and therefore the slope is infinity or undefined.
Slope of a horizontal line parallel to the x-axis is zero. Slope of a vertical line parallel to the y-axis is undefined.
ok thanks! I'm a freshman and my class is with sophomores and juniors @o@
You are welcome. Are you taking advanced math?
I guess you could call it that. Im in Algebra 2 honors because i took Geometry over the summer!
cool. Do well.
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