(i square root of 10 - 4) (i square root of 10 + 4)
i as in imaginary i not variable
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OpenStudy (anonymous):
\[\left( i \sqrt{10}-4 \right)\left( i \sqrt{10} +4\right)\]
OpenStudy (phi):
I would use
(a+b)(a-b)= a^2 - b^2
OpenStudy (anonymous):
would you mind explaining a bit more?
OpenStudy (phi):
do you know how to multiply two binomials (some people use FOIL) ?
OpenStudy (anonymous):
oh yes sorry I was confused for a second
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OpenStudy (phi):
using just (a+b)(a-b) we get a^2 -ab +ab-b^2 which simplifies to a^2 - b^2
(we usually remember this as how to factor a *difference of squares* )
you can use FOIL, or you can use the "short-cut"
\[ \left( i \sqrt{10}-4 \right)\left( i \sqrt{10} +4\right) = ( i \sqrt{10})^2 - 4^2 \]
OpenStudy (phi):
now you need to know what i*i is
and what \( \sqrt{10} \cdot \sqrt{10} \) is
OpenStudy (anonymous):
i*i is -1
\[\sqrt{10} * \sqrt{10} is 10\]
OpenStudy (phi):
ok, now simplify
\[ ( i \sqrt{10})^2 - 4^2 \]
OpenStudy (anonymous):
-26
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