(i square root of 10 - 4) (i square root of 10 + 4) i as in imaginary i not variable
\[\left( i \sqrt{10}-4 \right)\left( i \sqrt{10} +4\right)\]
I would use (a+b)(a-b)= a^2 - b^2
would you mind explaining a bit more?
do you know how to multiply two binomials (some people use FOIL) ?
oh yes sorry I was confused for a second
using just (a+b)(a-b) we get a^2 -ab +ab-b^2 which simplifies to a^2 - b^2 (we usually remember this as how to factor a *difference of squares* ) you can use FOIL, or you can use the "short-cut" \[ \left( i \sqrt{10}-4 \right)\left( i \sqrt{10} +4\right) = ( i \sqrt{10})^2 - 4^2 \]
now you need to know what i*i is and what \( \sqrt{10} \cdot \sqrt{10} \) is
i*i is -1 \[\sqrt{10} * \sqrt{10} is 10\]
ok, now simplify \[ ( i \sqrt{10})^2 - 4^2 \]
-26
yes
thank you
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