Function notation question. Please help!
Go ahead
Given : \[f(x)=\sqrt{4-x^2}\] & \[g(x)=\sqrt{1+x}\] Find : \[f+g(\sqrt{2})\]
Is it \(f\circ g(\sqrt{2})\)?
There is an addition symbol so I don 't think so.
\[(f+g)(\sqrt{2})\] like that right...
I guess so...
So, what's your attempt?
Would be easier to do \[(f+g)(x) \] first then \[(f+g)(\sqrt{2})\]
Ok, that makes more sense, I'll let batman take it
Ah, sorry to intrude Fibonacci, but you can take it away if you like :)
Well, I inserted f and g into the equation. But, since there were no parenthesis around f+g, i multiplied the square root of 2 by the square root 1+x to get the square root of 2+2x
It's probably not right, I'm really confused.
Well, what is it asking you for? it's asking for f+g, so what is f+g in terms of x?
like if you have two recipes, recipe f and recipe g, and you add the ingredients together to make one total recipe
what do you do?
I 'm not sure...
Ah so your question is asking, f(x)+g(2^1/2) basically, it's just hard to know what exactly you're asking unless you take a picture of the question itself and post it.
\[f(x)+g(x) = (f+g)(x)\]
You can see you're just factoring out the x.
that's what I'm interpreting it as batman
I'm just trying to think of a real world isomorphism
Yeah it doesn't make much sense though without parenthesis
I'll get a picture, two sec.
Np, :)
cooleos
It's the question to the left.
that is a poorly written question...
but I think batman's interpretation should be fine
Tell my math teacher that. XD
gladly
Yeah it's asking (f+g)(2^1/2) otherwise it's written wrongly.
So how do I attempt it?
So as I mentioned before find \[(f+g)(x) \] first meaning, add the two equations.
so have you ever baked, gotten two separate checks or something similar?
Yes.
\[f(x)=\sqrt{4-x^2} ~~~g(x) = \sqrt{1+x} ~~~ (f+g)(x) \implies (\sqrt{4-x^2})+(\sqrt{1+x})\]
Well you can't really do much I suppose so just skip to \[(f+g)(\sqrt{2})\]
so, if you bake and you want to double your recipe or add two recipes together, what do you do?
(I'm just explaining concept, batman's is the math speak)
Haha, well \[(f+g)(\sqrt{2}) \implies (\sqrt{4-\sqrt{2}^2})+(\sqrt{1+\sqrt{2}})\]
This is how I originally attempted it. I then assumed that I could use the quadratic formula. I'm guessing this is wrong ? @iambatman @fibonaccichick666
ahhh ok so example: if we have h(x)=x^2 then h(2)=2^2 DO YOU SEE?
sorry for caps hit the caps lock key
Yes, I see.
So would that be right ?
no, not quite
Ah, I see.
so I think the issue is notation that was not explained properly, Your intuition was great to just multiply the two, but you want to substitute the number for all of the x's
I plug in the square root of 2 for x
YES! :) technically... as written, you are correct and could argue that that is what the teacher asked you to do, but I don't recommend it
although you wouldn't square it as you did
Yeah, would you mind guiding me through the rest. I 'm really bad with radicals...
well to start, just tell me what (f+g)[of](x)=? I added the of because that is how you would say it, it doesn't get written that way. Also are you better with exponents?
Yes, I'm pretty good\[\sqrt{4-(\sqrt{2})^2}+\sqrt{1+(\sqrt{2})}\] with exponents.
Try simplifying it
so first, that is (f+g)(√2), second, a square root is just the exponent 1/2
\[\sqrt{2}^2\] like what does this mean? :P
\[\sqrt{2}+\sqrt{1+\sqrt{2}}\]
Yeah, that's good.
That's your final answer
Really ?
yup
Yeah unless you have a calculator
I do.
then you can get a numeric answer, however, it will not be exact
I think I'm supposed to leave it like this so thanks for the help you guys.
Np :)
np :)
Now, make sure you tell your teacher that they missed a vital thing in the question. Those parentheses are really important for meaning in the question ;P
Will do.
Hey this was troubling me, and I looked into it, I guess I haven't done this in a while but the notation is fine, but it does imply what we did, so if you have \[f-g(x) \] it's the same thing as \[(f-g)(x)\] thought I'd get that straight. :)
thanks, I'd never seen it written that way before either
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