standard form?? y=-5x-7 would be 7=-5x+y right? A cant be negative though...
@zepdrix
Correct, A cannot be negative :) But let's fix a little mistake first.
ok, is it the order of the numbers?
\[\Large\rm y=-5x-7\]To get this into standard form, we'll ADD 5x to each side, yes?
i though you added the 7
crap maybe ive been doing all of my problems wrong
Ok let's try doing that and see what happens.\[\Large\rm y+7=-5x\cancel{-7+7}\]\[\Large\rm y+7=-5x\]
it's fine to do it this way, it just leaves you with an extra step. See how we now need to move the y to the other side?
yep!
Subtracting y from each side gives us:\[\Large\rm 7=-5x-y\]But as you pointed out, your coefficient on the A is negative here. So we need to fix that.
do we multiply each side by -1
Just as we can add or subtract a quantity from each side and it stays balanced, we can also multiply, yes good.
so if we multiplied we would get -7=5x+y or -y?
We're distributing the -1 to each term on the right. So both the sign on the x and y will change.
So yes, +y.
\[\Large\rm y=-5x-7\]Notice that if we has just moved the 5x instead of moving the 7 and y and multiplying by -1, it would have saved us a few steps :) \[\Large\rm y+5x=\cancel{5x-5x}-7\]\[\Large\rm y+5x=-7\]
ok, that makes it easier! thanks! I just started algebra 2 today and there are a lot of sophomores and juniors in my class @0@
Are you younger than that? :o
ya im a freshman
Haha that's always fun XD Being the young one in the class. You'll look like the smarty pants lol
hopefully.... I'll probably look really stupid when we actually get to a new topic
:3
thanks again!
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