Can anyone help me with this? And explain how it go or how it get? .. :/ Heres the question ... Frieght train cars usually carry of maximum net weight of about 100,000 lbs. if a train is carrying three cars of concentrated sufuric acid (assume that it is 96% acid) how much lime [Ca (CH2)2] would be required to neutralize the acid if it is spilled in a derailment or wreck? the neutrlization reaction is H2SO4 + Ca (CH)2 + CaSO4 + 2H2O .. :/ :3 ..
1. First notice that you need to multiply 100,000 lbs by 3 2. Next you need to convert pounds to kilograms 1kg = 2.204lbs 3. Next convert kilograms to grams 1000g = 1kg 4. Convert kg of Sulphuric acid to moles Moles = grams/molecular mass If you dont know how to calculate molecular mass of a compound simply click one of the videos here it will explain it: https://www.youtube.com/results?search_query=how+to+calculate+molecular+mass 5. Balance the reaction equation, if you dont know how to balance a reaction equation click a video here it will explain it: https://www.youtube.com/results?search_query=how+to+balance+a+reaction+equation 6. Divide the moles of sulphuric acid by the number next to sulphuric acid and multiply by the number next to the calcium hydroxide Ca(OH)2 [Ca(CH2)2 is not lime it is likely a mistake by you or the author]. Doing this will give you the moles of lime needed. 7. Find the mass of lime from the moles using the formula, Moles = grams/molecular mass
H2SO4 + Ca(OH)2 → CaSO4 + 2 H2O (3 cars) x (100000 lbs/car) x (0.96) / (98.0791 g H2SO4/mol) x (1 mol Ca(OH)2 / 1 mol H2SO4) x (74.0927 g Ca(OH)2/mol) = 2.18 x 10^5 lb Ca(OH)2
Thanks you very much your a great help :) ..
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