Question

WILL GIVE MEDALLL

The table below shows the distance d(t) in feet that an object travels in t seconds:

What is the average rate of change of d(t) between 3 seconds, and 5 seconds and what does it represent?
59.5 ft/s; it represents the average speed of the object between 3 seconds and 5 seconds

112 ft/s; it represents the average speed of the object between 3 seconds and 5 seconds

112 ft/s; it represents the average distance traveled by the object between 3 seconds and 5 seconds

59.5 ft/s; it represents the average distance traveled by the object betwe

Answer 1

Please helppp

Answer 2

Before I begin to answer your question, what approaches have you made to solve this problem?

Answer 3

Well, I was thinking it was C because it's asking how much distance has the object traveled within 3-5 seconds.. Am I right?

Answer 4

No, since rate is units/ unit of time, that means our final result in this problem will be in ft/s. What property is in units of distance per unit time?

Answer 5

Okay, so B? It would be in speed instead of distance?

Answer 6

Yes. The reason is \[speed = \frac {distance}{time}\] Therefore, since we want to know the average rate of change from second 3 to second five, our formula is \[speed = \frac {350 ft - 126 ft}{5s - 3 s} = 112 \frac {ft}{s}\]

Answer 7

Remember, average rate of change simply means \[rate = \frac {unit}{time}\]

Answer 8

Oh, okay! That makes sense, I understand now. Thank you so much :)

Answer 9

No problem

Answer 10

Can you help me with a couple more maybe?