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Geometry 6 Online
OpenStudy (anonymous):

If line AD = 11 cm and line AB = 25 cm, calculate the length of line AC.

OpenStudy (anonymous):

OpenStudy (anonymous):

The secant-tangent rule is (whole secant) * (external part) = tangent^2. Therefore, to find the length of AC, you need to solve the equation \[AC*AD = AB^2\]

OpenStudy (anonymous):

I think I'm doing something wrong. The answer I got was 22.45.

OpenStudy (anonymous):

Can you run by your math step by step?

OpenStudy (anonymous):

That is your error. It's 11*x not 11+x and 25^2, not just 25

OpenStudy (anonymous):

Okay, here's my step-by-step. 1. (11 + CD) 11 = 25 squared 2. 121 + 11CD = 625 3. CD = 45.82. Alright, I see I made a mistake on my last calculation. But 45.82 isn't one of my options for an answer. Any thoughts?

OpenStudy (anonymous):

You don't need to separate AC into AD and DC, all you need to do is \[AC*11 = 625\] \[AC = 56.8\]

OpenStudy (anonymous):

Oh! Thanks for the clarification. That helps a lot!

OpenStudy (anonymous):

AD*AC = AB^2

OpenStudy (anonymous):

x=56.8

OpenStudy (anonymous):

11*x=625 so x=56.81

OpenStudy (anonymous):

That looks right.

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