If line AD = 11 cm and line AB = 25 cm, calculate the length of line AC.
The secant-tangent rule is (whole secant) * (external part) = tangent^2. Therefore, to find the length of AC, you need to solve the equation \[AC*AD = AB^2\]
I think I'm doing something wrong. The answer I got was 22.45.
Can you run by your math step by step?
That is your error. It's 11*x not 11+x and 25^2, not just 25
Okay, here's my step-by-step. 1. (11 + CD) 11 = 25 squared 2. 121 + 11CD = 625 3. CD = 45.82. Alright, I see I made a mistake on my last calculation. But 45.82 isn't one of my options for an answer. Any thoughts?
You don't need to separate AC into AD and DC, all you need to do is \[AC*11 = 625\] \[AC = 56.8\]
Oh! Thanks for the clarification. That helps a lot!
AD*AC = AB^2
x=56.8
11*x=625 so x=56.81
That looks right.
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