Please help with this someone
Ive worked out I and II but I'm not too sure whether my answer is right for III II) X Coordinate of A is 4.5
III my answer is 34.13603897 pi
did you break the region R into two separate regions?
What are some intermediate steps you've got
i was taught to combine the two equations
What area did you get for R?
okay here is how i started
you have to break the regions into two parts \[R=\int_0^4f(x)\,\mathrm dx+\int_4^{4.5}L(x)\mathrm dx\]
okay thanks. But how did you get the limits?
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ohhh i see so it's not possible to just combine the equation and integrate that?
Also do i just Find the volume of both R regions and then add them together?
find R_1, and R_2, add them together to get R, then find the volume
okay thank you
once you've proven or gotten the equation of line L, you needn't do that extra step you base it on the total shaded area under the curve
if you show your solution to (i) it'd be easier to validate your volume solution
so you have curved equation of \[y = \sqrt{x}\] that intersects line L at point (4,2) and it also says that L is normal to the graph go back to definitions Normal line is the line perpendicular to the tangent at the point of tangency
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