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Mathematics 19 Online
OpenStudy (anonymous):

Please help with this someone

OpenStudy (anonymous):

OpenStudy (anonymous):

Ive worked out I and II but I'm not too sure whether my answer is right for III II) X Coordinate of A is 4.5

OpenStudy (anonymous):

III my answer is 34.13603897 pi

OpenStudy (unklerhaukus):

did you break the region R into two separate regions?

OpenStudy (unklerhaukus):

What are some intermediate steps you've got

OpenStudy (anonymous):

i was taught to combine the two equations

OpenStudy (unklerhaukus):

What area did you get for R?

OpenStudy (anonymous):

okay here is how i started

OpenStudy (unklerhaukus):

you have to break the regions into two parts \[R=\int_0^4f(x)\,\mathrm dx+\int_4^{4.5}L(x)\mathrm dx\]

OpenStudy (anonymous):

okay thanks. But how did you get the limits?

OpenStudy (unklerhaukus):

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OpenStudy (unklerhaukus):

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OpenStudy (anonymous):

ohhh i see so it's not possible to just combine the equation and integrate that?

OpenStudy (anonymous):

Also do i just Find the volume of both R regions and then add them together?

OpenStudy (unklerhaukus):

find R_1, and R_2, add them together to get R, then find the volume

OpenStudy (anonymous):

okay thank you

OpenStudy (nincompoop):

once you've proven or gotten the equation of line L, you needn't do that extra step you base it on the total shaded area under the curve

OpenStudy (nincompoop):

if you show your solution to (i) it'd be easier to validate your volume solution

OpenStudy (nincompoop):

so you have curved equation of \[y = \sqrt{x}\] that intersects line L at point (4,2) and it also says that L is normal to the graph go back to definitions Normal line is the line perpendicular to the tangent at the point of tangency

OpenStudy (nincompoop):

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