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Mathematics 10 Online
OpenStudy (anonymous):

Find f(x) and g(x) so the function can be expressed as y = f(g(x)).

OpenStudy (anonymous):

\[y=(8/x^2)+4\]

OpenStudy (anonymous):

@hartnn @phi @Whitemonsterbunny17

hartnn (hartnn):

multiple answers, let me give you an example : if f(g(x)) = \(\Large e^{x^2+4}\) you can take f(x) = e^x , g(x) = x^2+4

hartnn (hartnn):

example 2 : f(g(x)) = 9+10/ log x so f can be taken as 9+x and g as 10/log x OR f can be taken as 9+10/x g as log x both gives f(g(x)) = 9+10/ log x

OpenStudy (kc_kennylau):

And of course, you can always set g(x) = x

OpenStudy (anonymous):

Okay so i basically make up the f(g(x)) to an extent then pull the f(x) and g(x) out of that?

hartnn (hartnn):

didn't get you... try to get f and g for 8/x^2 +4 and let me know, if there is any error, i'll correct you :)

OpenStudy (anonymous):

f=x^2+4 g=8 ?

OpenStudy (anonymous):

functions have always confused me

hartnn (hartnn):

your g is constant and you can't take x^2+4 as one function, the question is \(\dfrac{8}{x^2}+4\) and not 8/(x^2+4) right ?

OpenStudy (anonymous):

Right

hartnn (hartnn):

easiest thing you can do is to try and take 1st term as f (8/x^) and see what 'g' you can take to make f(g(x)) as 8/x^2+4

hartnn (hartnn):

**f =(8/x^2)

OpenStudy (anonymous):

Oh! *click*

OpenStudy (anonymous):

I get it

hartnn (hartnn):

so what f and g functions did u choose ?

OpenStudy (anonymous):

f=8/x^2 g=4

hartnn (hartnn):

nopes

OpenStudy (anonymous):

darn

hartnn (hartnn):

sorry i meant g= 8/x^2 and find 'f'

hartnn (hartnn):

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