Find f(x) and g(x) so the function can be expressed as y = f(g(x)).
\[y=(8/x^2)+4\]
@hartnn @phi @Whitemonsterbunny17
multiple answers, let me give you an example : if f(g(x)) = \(\Large e^{x^2+4}\) you can take f(x) = e^x , g(x) = x^2+4
example 2 : f(g(x)) = 9+10/ log x so f can be taken as 9+x and g as 10/log x OR f can be taken as 9+10/x g as log x both gives f(g(x)) = 9+10/ log x
And of course, you can always set g(x) = x
Okay so i basically make up the f(g(x)) to an extent then pull the f(x) and g(x) out of that?
didn't get you... try to get f and g for 8/x^2 +4 and let me know, if there is any error, i'll correct you :)
f=x^2+4 g=8 ?
functions have always confused me
your g is constant and you can't take x^2+4 as one function, the question is \(\dfrac{8}{x^2}+4\) and not 8/(x^2+4) right ?
Right
easiest thing you can do is to try and take 1st term as f (8/x^) and see what 'g' you can take to make f(g(x)) as 8/x^2+4
**f =(8/x^2)
Oh! *click*
I get it
so what f and g functions did u choose ?
f=8/x^2 g=4
nopes
darn
sorry i meant g= 8/x^2 and find 'f'
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