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Mathematics 10 Online
OpenStudy (anonymous):

I need help !!!!FRANTIC!!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

which one?

OpenStudy (anonymous):

mainly all of them but to start off the first 1

OpenStudy (anonymous):

k find a perfect square inside the radical and pull it out like this \[\sqrt{32}=\sqrt{16\times 2}=\sqrt{16}\sqrt2=4\sqrt2\] you do those steps in your head, i only wrote it out like that so you could see what i was thinking

OpenStudy (anonymous):

that makes \[4\sqrt{32}=4\times 4\sqrt2=16\sqrt2\] repeat the process for \(6\sqrt{50}\)

OpenStudy (anonymous):

let me know what you get once you do that we will combine like terms

OpenStudy (anonymous):

42

OpenStudy (anonymous):

forty two?

OpenStudy (anonymous):

what did you get for \(6\sqrt{50}\) ?

OpenStudy (anonymous):

6 square root of 50 is 42.42

OpenStudy (anonymous):

ok i think you are not getting what you are supposed to do there are no decimals approximations or calculators involved here you answer needs to look like some number times \(\sqrt2\)

OpenStudy (anonymous):

the idea is to write each number in simplest radical form do you see how i turned \(4\sqrt{32}\) in to \(16\sqrt2\) ?

OpenStudy (anonymous):

yes looks like you half 32 and 4 and flipped t

OpenStudy (anonymous):

\[3\sqrt{25}\]

OpenStudy (anonymous):

or flip it is that rght

OpenStudy (anonymous):

not quite i did not take half of 32

OpenStudy (anonymous):

im just confused on how to work square roots

OpenStudy (anonymous):

the reason for the 16 out front was not that i took half of 32

OpenStudy (anonymous):

k let me ask a simpler question what is \(\sqrt{16}\) ?

OpenStudy (anonymous):

4

OpenStudy (anonymous):

right

OpenStudy (anonymous):

that makes \[\sqrt{16}\sqrt{2}=4\sqrt{2}\]

OpenStudy (anonymous):

now what is \(\sqrt{25}\) ?

OpenStudy (anonymous):

5

OpenStudy (anonymous):

k good what makes \[\sqrt{50}=\sqrt{25}\sqrt{2}=5\sqrt2\]

OpenStudy (anonymous):

i meant "that makes"

OpenStudy (anonymous):

so 5 of a square root

OpenStudy (anonymous):

right

OpenStudy (anonymous):

so its 5

OpenStudy (anonymous):

in total you have \[4\times 4\sqrt2+6\times 5\sqrt2=16\sqrt2+30\sqrt2\]

OpenStudy (anonymous):

so to finish, since they already put the \(\sqrt2\) in the problem all you have left to do is add \(16+30\)

OpenStudy (anonymous):

thank you so so so much @satellite73

OpenStudy (anonymous):

yw want to do the next one too?

OpenStudy (anonymous):

yes if you have time and dont mind

OpenStudy (anonymous):

sure this time we go quicker \[50\times 22=1100=11\times 100\]

OpenStudy (anonymous):

and \[\sqrt{11\times 100}=\sqrt{11}\sqrt{100}=10\sqrt{11}\]

OpenStudy (anonymous):

you get \[3\times 10\times \sqrt{11}=30\sqrt{11}\]

OpenStudy (anonymous):

more or less clear?

OpenStudy (anonymous):

Clear

OpenStudy (anonymous):

k the last one is real easy because there is only one answer that makes sense

OpenStudy (anonymous):

\(\sqrt{y^2}=y\) so pick the only answer with a \(y\) outside the radical and no \(y\) inside the radical

OpenStudy (anonymous):

I would like to give you your ribbons but only able to give you one

OpenStudy (anonymous):

lol thanks, but i have plenty i can't redeem them for valuable prizes, but i appreciate the thanks

OpenStudy (anonymous):

Youre an awesome help

OpenStudy (anonymous):

ty

OpenStudy (anonymous):

so im suppose to multiply right 3 and 2 which would be 6

OpenStudy (anonymous):

which problem you talking about?

OpenStudy (anonymous):

Last one

OpenStudy (anonymous):

oh no careful

OpenStudy (anonymous):

you do not multiply anything certainly not the exponents lets go slow

OpenStudy (anonymous):

ignoring every part but this \(\sqrt{y^2}\) it should be clear that \(\sqrt{y^2}=y\)

OpenStudy (anonymous):

like for example \(\sqrt{5^2}=5\)

OpenStudy (anonymous):

oh so what you said before about it staying on the outside its 2y

OpenStudy (anonymous):

yeah , the \(y\) comes outside the radical

OpenStudy (anonymous):

\[\sqrt{\text{stuff }y^2}=y\sqrt{\text{stuff}}\]

OpenStudy (anonymous):

so i would actually get \[9xy \sqrt{2y}\]

OpenStudy (anonymous):

so pick the only answer without a \(y\) inside the radical no pick the one with NO \(y\) inside

OpenStudy (anonymous):

i.e. the last option

OpenStudy (anonymous):

oh i see why thank you

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