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OpenStudy (anonymous):
OpenStudy (anonymous):
which one?
OpenStudy (anonymous):
mainly all of them but to start off the first 1
OpenStudy (anonymous):
k
find a perfect square inside the radical and pull it out like this
\[\sqrt{32}=\sqrt{16\times 2}=\sqrt{16}\sqrt2=4\sqrt2\]
you do those steps in your head, i only wrote it out like that so you could see what i was thinking
OpenStudy (anonymous):
that makes
\[4\sqrt{32}=4\times 4\sqrt2=16\sqrt2\]
repeat the process for \(6\sqrt{50}\)
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OpenStudy (anonymous):
let me know what you get
once you do that we will combine like terms
OpenStudy (anonymous):
42
OpenStudy (anonymous):
forty two?
OpenStudy (anonymous):
what did you get for \(6\sqrt{50}\) ?
OpenStudy (anonymous):
6 square root of 50 is 42.42
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OpenStudy (anonymous):
ok i think you are not getting what you are supposed to do
there are no decimals approximations or calculators involved here
you answer needs to look like some number times \(\sqrt2\)
OpenStudy (anonymous):
the idea is to write each number in simplest radical form
do you see how i turned
\(4\sqrt{32}\) in to \(16\sqrt2\) ?
OpenStudy (anonymous):
yes looks like you half 32 and 4 and flipped t
OpenStudy (anonymous):
\[3\sqrt{25}\]
OpenStudy (anonymous):
or flip it is that rght
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OpenStudy (anonymous):
not quite
i did not take half of 32
OpenStudy (anonymous):
im just confused on how to work square roots
OpenStudy (anonymous):
the reason for the 16 out front was not that i took half of 32
OpenStudy (anonymous):
k let me ask a simpler question
what is \(\sqrt{16}\) ?
OpenStudy (anonymous):
4
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OpenStudy (anonymous):
right
OpenStudy (anonymous):
that makes \[\sqrt{16}\sqrt{2}=4\sqrt{2}\]
OpenStudy (anonymous):
now what is \(\sqrt{25}\) ?
OpenStudy (anonymous):
5
OpenStudy (anonymous):
k good
what makes
\[\sqrt{50}=\sqrt{25}\sqrt{2}=5\sqrt2\]
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OpenStudy (anonymous):
i meant "that makes"
OpenStudy (anonymous):
so 5 of a square root
OpenStudy (anonymous):
right
OpenStudy (anonymous):
so its 5
OpenStudy (anonymous):
in total you have
\[4\times 4\sqrt2+6\times 5\sqrt2=16\sqrt2+30\sqrt2\]
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OpenStudy (anonymous):
so to finish, since they already put the \(\sqrt2\) in the problem all you have left to do is add \(16+30\)
OpenStudy (anonymous):
thank you so so so much @satellite73
OpenStudy (anonymous):
yw
want to do the next one too?
OpenStudy (anonymous):
yes if you have time and dont mind
OpenStudy (anonymous):
sure
this time we go quicker
\[50\times 22=1100=11\times 100\]
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OpenStudy (anonymous):
and \[\sqrt{11\times 100}=\sqrt{11}\sqrt{100}=10\sqrt{11}\]
OpenStudy (anonymous):
you get \[3\times 10\times \sqrt{11}=30\sqrt{11}\]
OpenStudy (anonymous):
more or less clear?
OpenStudy (anonymous):
Clear
OpenStudy (anonymous):
k
the last one is real easy because there is only one answer that makes sense
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OpenStudy (anonymous):
\(\sqrt{y^2}=y\) so pick the only answer with a \(y\) outside the radical and no \(y\) inside the radical
OpenStudy (anonymous):
I would like to give you your ribbons but only able to give you one
OpenStudy (anonymous):
lol thanks, but i have plenty
i can't redeem them for valuable prizes, but i appreciate the thanks
OpenStudy (anonymous):
Youre an awesome help
OpenStudy (anonymous):
ty
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OpenStudy (anonymous):
so im suppose to multiply right 3 and 2 which would be 6
OpenStudy (anonymous):
which problem you talking about?
OpenStudy (anonymous):
Last one
OpenStudy (anonymous):
oh no careful
OpenStudy (anonymous):
you do not multiply anything
certainly not the exponents
lets go slow
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OpenStudy (anonymous):
ignoring every part but this \(\sqrt{y^2}\) it should be clear that \(\sqrt{y^2}=y\)
OpenStudy (anonymous):
like for example \(\sqrt{5^2}=5\)
OpenStudy (anonymous):
oh so what you said before about it staying on the outside its 2y
OpenStudy (anonymous):
yeah , the \(y\) comes outside the radical
OpenStudy (anonymous):
\[\sqrt{\text{stuff }y^2}=y\sqrt{\text{stuff}}\]
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OpenStudy (anonymous):
so i would actually get \[9xy \sqrt{2y}\]
OpenStudy (anonymous):
so pick the only answer without a \(y\) inside the radical
no
pick the one with NO \(y\) inside