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Can u help please? (graph attached) If the probability of the shaded area is 60%, find P(X≤3)
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the whole region has to be \(100\%\) subtract \(60\%\) to give the unshaded part, then take half of that
ok thx ill try that
ummm ok that doesnt make any sence to me sry subtract 60% from what?
@satellite73
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|dw:1408543790992:dw| You can set up an equation as satellite mentioned: \[\underbrace{A}_{\large P(X\le3)}+\underbrace{60}_{\large P(3\le X\le5)}+\underbrace{A}_{\large P(X\ge5)}=\underbrace{100}_{\large\text{total area}}\] Solve for \(A\).
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