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Mathematics 15 Online
OpenStudy (anonymous):

Can u help please? (graph attached) If the probability of the shaded area is 60%, find P(X≤3)

OpenStudy (anonymous):

OpenStudy (anonymous):

the whole region has to be \(100\%\) subtract \(60\%\) to give the unshaded part, then take half of that

OpenStudy (anonymous):

ok thx ill try that

OpenStudy (anonymous):

ummm ok that doesnt make any sence to me sry subtract 60% from what?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

|dw:1408543790992:dw| You can set up an equation as satellite mentioned: \[\underbrace{A}_{\large P(X\le3)}+\underbrace{60}_{\large P(3\le X\le5)}+\underbrace{A}_{\large P(X\ge5)}=\underbrace{100}_{\large\text{total area}}\] Solve for \(A\).

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