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Find 3x^2 - y^3 - y^3 - z if x = 3, y = -2, and z = -5. Numerical Answers Expected! I got 92, is that right?
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Pretty sure it's wrong though lol
nope...not really
I got 48
I think it is wrong Just break it down... What is 3x^2 if x=3 What is y^3 if y= -2 don't forget you are subtracting y^3 in the equation....
\[3x^2-y^3-y^3-z\] so, we substitute \[3(3^2)-(-2^3)-(-2^3)-(-5)=3(9)-(-8)-(-8)-(-5)\] \[27+8+8+5=48\]
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o3o welp I'm going to submit this lol
and it was right! :p
My reply was to your first answer of 92 - sorry for confusion. 48 is correct
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