Question

Here dude

Answer 1

<bangs on table>
WHERE IS IT?!

Answer 2

\[3m^2+8m-3=0\] Quadratic formula

Answer 3

...srsly bro? :D

Answer 4

Tell me you were able to answer this... :D

Answer 5

no it was an example from my teacher....I dont really know howd he get it

Answer 6

I see. Do you know the quadratic formula? :)

Answer 7

I forgot my friend.... :(

Answer 8

You forgot your friend...?
I expect he or she isn't too happy about that :D #MissingComma

...anyway

Ask anyone what the quadratic formula is, he'd probably go
\[\Large x = \frac{-\color{blue}b \pm \sqrt{\color{blue}b^2 - 4\color{red}a\color{green}c}}{2\color{red}a}\]
This look familiar?

Answer 9

Genius Kid

Answer 10

No... this is high school stuff... get a grip, Josh haha

Anyway, does this formula look familiar to you?

Answer 11

Its exactly the same on my notebook

Answer 12

Okay... do you know how to use it? lol

Answer 13

No...

Answer 14

Well, no matter, that's why I'm here, *Kuya* ;)
I find colour coding makes thing easier, wouldn't you say?
\[\Large x = \frac{-\color{blue}b \pm \sqrt{\color{blue}b^2 - 4\color{red}a\color{green}c}}{2\color{red}a}\]
\[\Large \color{red}3m^2\color{blue}{+8}m\color{green}{-3}=0\]
Does this give you an idea? ^_^

Answer 15

Ok kapatid...Yeah slightly

Answer 16

Okay, basically, \(\large \color{red}a\) is the coefficient of the SQUARE... the m with the 2 on top.
\(\large \color{blue}b\) is the coefficient of the other m, the one with NO 2 on top.

\(\large \color{green}c \) is the CONSTANT, the one with no m.

So tell me, what are your values for a, b, and c?

Answer 17

3,8 n -3

Answer 18

Well there you go, just plug them in :)

Answer 19

\[\Large x = \frac{-\color{blue}{8} \pm \sqrt{\color{blue}8^2 - 4\color{red}{(3)}\color{green}{(-3)}}}{2\color{red}{(3)}}\]

Answer 20

oh i see

Answer 21

But ther's m1 and m2

Answer 22

Of course. There will be TWO solutions.
Note this sign:
\[\Large x = \frac{-\color{blue}{8} \boxed\pm \sqrt{\color{blue}8^2 - 4\color{red}{(3)}\color{green}{(-3)}}}{2\color{red}{(3)}}\]
m1 treats that sign as +
m2 treats it as -

Or vice versa. It doesn't really matter, as long as you have the two solutions.

Answer 23

ok
thx