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Mathematics 12 Online
OpenStudy (anonymous):

Calculus questions! I have three questions regarding limits and continuous functions I will just need a minute to type the equations in!

OpenStudy (anonymous):

\[\lim_{x \rightarrow 1} \frac{ x^3-1 }{ x^2-1 }\]

OpenStudy (anonymous):

2.) \[\lim_{t \rightarrow 9} \frac{ 9-t }{ 3-\sqrt{t}}\]

OpenStudy (xapproachesinfinity):

the first one is it x^3-1/x^2-1

OpenStudy (anonymous):

Yes it is

OpenStudy (anonymous):

3.) find the values of c so that f(x) is continuous on the entire real number line when \[f(x)=\left\{ x-2, x≤5 \right\} \left\{ cx-3, x>5 \right\}\] *both equations are supposed to be the one bracket (like how a piecewise function is set up)

OpenStudy (xapproachesinfinity):

i assume it is like that and continue. the discontinuity of that expresssion is when x=1 \(\Large \rm\color{midnightblue}{\lim_{x\to1}\frac{x^3-1}{x^2-1}=\lim_{x\to1}\frac{\cancel{(x-1)}(x^2+x+1)}{\cancel{(x-1)}(x+1)}=lim_{x\to1}\frac{x^2+x+1}{x+1}=\\lim_{x\to1}\frac{1+1+1}{1+1}=3/2}\)

OpenStudy (xapproachesinfinity):

the second multiply top and bottom by the conjugate \(3+\sqrt{t}\)

OpenStudy (xapproachesinfinity):

for 3 if f is continuous then the limit must exist and therefore \(\Large \rm\color{midnightblue}{lim_{x\to5^-}f(x)=lim_{x\to5^+}f(x)}\) set this equation and solve for c

OpenStudy (anonymous):

Thanks for all your help!

OpenStudy (xapproachesinfinity):

Anytime! i hope you got the answers^_^

OpenStudy (xapproachesinfinity):

but i think you are okay with algebra :)

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