Question

2N2 + 4H2O + O2 = 2NH4NO3
How many numbers of molecules of water vapor and oxygen are produced if we have 6.022 X 10^23 molecules of nitrogen?

Answer 1

No water or oxygen is produced. Water and oxygen are consumed by the reaction.
As to how much of each is consumed:
Twice as much (in moles or atoms) water is consumed as nitrogen, and half as much water as nitrogen, so it's
12.044 x 10^23 molecules of water and 3.011 x 10^23 molecules of oxygen.

Answer 2

alright that's what i thought...Thanks Tech1

Answer 3

I should have said before: As the equation is written no water or oxygen is produced. But after looking at the equation closely, the reaction as written is not likely to happen. It's much more likely to be a decomposition:
2 NH4NO3 → 2 N2 + 4 H2O + O2
in which case nitrogen, water and oxygen are produced. (The quantities of water and oxygen are the same as before.)