Mathematics
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undeadknight26 (undeadknight26):
Let f(x) = 5x + 12. Find f-1(x).
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undeadknight26 (undeadknight26):
So far i have:
f(x) = 5x + 12
y = 5x + 12
x = 5y + 12
sqrtx = sqrt5y + 12
OpenStudy (anonymous):
Find y there in terms of x..
undeadknight26 (undeadknight26):
I have (x - 12)/(5)
OpenStudy (anonymous):
I mean from this equation : x = 5y + 12
Finding y in terms of x..
\(x - 12 = 5y\)
undeadknight26 (undeadknight26):
Or would it be (5)/x - 12?
Im quite sure its (x-12)/(5)
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OpenStudy (anonymous):
What else, replace y with \(f^{-1}(x)\) there..
OpenStudy (acxbox22):
you are right
undeadknight26 (undeadknight26):
I am?
undeadknight26 (undeadknight26):
its (x-12)/(5)? @acxbox22
OpenStudy (anonymous):
Yes, what you have is what you are looking for.. :)
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OpenStudy (anonymous):
Yep..
OpenStudy (acxbox22):
yes that is the inverse
y=(x-5)/12
undeadknight26 (undeadknight26):
Thank you very much!
OpenStudy (anonymous):
Yes, but why are you missing LHS??
Do write LHS there with your answer.. :)
undeadknight26 (undeadknight26):
LHS?
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OpenStudy (anonymous):
You have:
\[y = \frac{x-12}{5} \implies f^{-1}(x) = \frac{x-12}{5}\]
OpenStudy (anonymous):
LHS : Left Hand Side
RHS : Right Hand Side..
An equation must contain LHS and RHS..
OpenStudy (acxbox22):
true..i forgot that
undeadknight26 (undeadknight26):
I seem to have not learned that yet...Will do because maybe i can get extra credit!
OpenStudy (anonymous):
I am just saying, that you should not (x-12)/5 alone..
Do mention what is it equal to..
It is actually : y = ..........