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Are you seeing any x in your expression??
In f(3), 3 is x as you represent your function as f(x), so value inside brackets of f, will be x.. So, here x = 3.. And you have : f(x) = x - 7 Here where, you see x, just replace it with 3 and check what you got.. :)
Oh wow..! Going good.. Yes, solve it further.. :)
How, -4/3??
Yes, then you will write : For x = 3 f(3) = 3 - 7 f(3) = ??
-4
Yes, that's it.. f(3) = -4
Them?? Whom ??
Hey, that is representation of function. f(x) is general representation of any function, f(x) does not mean (x) is getting multiplied with f..
Ohhh okayy got it
So is the final answer f(3) = -4?
Whenever you will write function, you will write like : f(x), g(y), h(z) etc..
In f(3), it does not imply 3 is multiplied with f and don't find f here in any way.. Yes, f(3) = -4 is your final answer.. Basically, f(x) = x - 7 means that at x, your function f has value of x - 7 f(3) = -4 means at x = 3, your function will have value of -4..
So the inverse of f(x) = 4x – 7
Is this the same question?? How does 4 come with x here??
That's what the original equation is, f(x) = 4x – 7
Okay.. Here, there is a standard procedure to find f inverse, Oh wait..
What the hell..!! My mistake, sorry.. I thought the question is f(x) = x - 7.. Sorry, sorry.. Yes, there you will multiply 4 with x surely..
So was the first part wrong?
f(x) = 4(3) – 7 which I switch it to that?
Yes, sorry.. f(x) = 4x - 7 f(3) = 4(3) - 7 f(3) = 12 - 7 f(3) = 5
Okay got it! As for the inverse I think I got it on my own, could you just check my work?
This is now correct, I earlier misinterpreted the question, Sorry...
Yeah, sure go ahead..
Oh wait f(x) should be replaced with y my bad
Ughh i feel like I did it wrong
Yeah stuck and confused:(
Don't worry, I am here to make it correct.. :)
Thank you
First write the function given: f(x) = 4x - 7 Now, put f(x) = y (Not x, you did wrong here itself) so, you get : y = 4x - 7 Now, find x in terms of y here: y + 7 = 4x - 7 + 7 y + 7 = 4x Divide by 4 both the sides: \[x = \frac{y+7}{4}\] Now, change x with y and y with x: \[y = \frac{x+7}{4}\] This y is now f inverse, so replace y here with \(f^{-1}(x)\) So, finally you will get: \[f^{-1}(x) = \frac{x + 7}{4}\]
Omg thanks so much your a lifesaver!
Getting all that??
Yeah I am!
Will you try one if I give one to you??
I'll try:P I still have to work on another problem
It will not take much time, instead it will clear your concepts.. Find inverse for f(x) = 3x + 2
and then subtract to on both sides, so -2 = 3y
How you got 3y ??
or wait y - 2 = 3y?
I just subtracted two on both sides
Put f(x) = y and not x = y..
See, you have f(x) = 3x + 2 Just replace f(x) with y, not x with y here.. You will get : y = 3x + 2 f(x) and x are two different things..
Ohhh okay I understand
So I subtract 2 now right? to make it y - 2 = 3x?
Yeah going good, proceed further..
Find x there in terms of y..
Then I divide 3x to make it x = y - 2/3x
You will divide with 3 only..
Why 3x ??
and then switch around the x and the y so its y = x - 2 / 3
Yes, though you got it right, here just replace y with f inverse of x..
so then f-1(x) = y = x - 2/3
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