Question

check all that apply, if tan e= 15/8, then:
A: csc e=17/15
B: cos e= 15/17
C: cot e= 8/15
D:sec e=17/8

Answer 1

definitely C. I haven't done the others though.

Answer 2

how do you solve this though? i need to learn for a test

Answer 3

well cot is the opposite of tan\[\tan=\frac{ opp }{ adj } ~~~~\cot=\frac{ adj }{ opp }\]

Answer 4

what about the rest

Answer 5

\[\sec=\frac{ 1 }{ \cos }~~so~~\sec=\frac{ hyp }{ adj }\]Do you see how it flips the cos?

Answer 6

no..

Answer 7

ok. So cosine is \[\frac{ adjacent }{ hypotenuse }\] Secant is the inverse of cosine. So you flip them\[\frac{ adjacent }{ hypotenuse }~~~goes \to~~~\frac{ hypotenuse }{ adjacent }\]Does that make sense? (sorry I'm at work, so I'm not able to explain as fast as I usually do.

Answer 8

okay so far that makes sense

Answer 9

what is the hypotenuse for this one though? like how do you find it out

Answer 10

Ok good deal. Do you know how to use the Pythagorean theorem? That's how you'd find the hypotenuse

Answer 11

yeah i do so would it be like a^2+ 15^2=8^2
if you do this then you get 12.68 but that doesnt seem right

Answer 12

Your 8 is in the wrong place. \[\tan=\frac{ opp }{ adj }\]You don't use hypotenuse for tan. \[8^{2}+15^{2}=c\]is what you'd use

Answer 13

\[c ^{2}\]sorry

Answer 14

oh wow im stupid! haha thank you

Answer 15

Haha, no I used to do it all the time. Eventually, you don't even think about which one is which.

Answer 16

Were you able to figure out the hypotenuse?