Question

please help! Question C)

Answer 1

The equation h(t) = a sin[b(t-c)] +d
has the amplitude: |a|
the period: \(\dfrac{2\pi}{b}\)
the horizontal phrase shift is c units to the right
the vertical phrase shift is d units up

Answer 2

i know that
period=25.7
amplitude=25
phase shift= -3.5
vertical shift= 30

Answer 3

im just not sure if that is in terms of cos or sin. Because the original coordinates when graphed is a cosine function but they ask for it in terms of a sine function

Answer 4

is it not that if you shift sin function a \(\pi/2\) units, you have cos one? or vice versa?

Answer 5

so then the cos function would be y=25cos(25.7(t+3.5)+30 what would the sin function be?

Answer 6

You give me the period of cos is 25.7, that means the number right after cos is 0.244 not as you said

Answer 7

the period is 14 seconds but 360/14=25.7

Answer 8

I mean 25cos0.244(t-3.5) +30

Answer 9

okay, so then the sin function is y=25sin(25.7(t+3.5)+30?

Answer 10

oh, I got you!! you calculated !!

Answer 11

why +3.5 not -3.5?

Answer 12

because -(-3.5) =+3.5 when put into the equation

Answer 13

ok, let it there
now convert cos to sin
the period is 25.7 , right? so 1/4*25.7 = 6.425

Answer 14

you move the cos back to the left 6.425 to get the sin one, right?
so sin becomes 25 sin(t-(-3.5+6.425) +30
got me?

Answer 15

okay

Answer 16

dat sit

Answer 17

okay thank you