Question

Find all the missing parts to the triangle below.

Answer 1

Anyone?

Answer 2

Still here.

Answer 3

I'm working on it.
You'll have your answer.
:-)

Answer 4

Thank you, I really appreciate it.

Answer 5

You need to use a combination of the law of cosines and the law of sines. The law of cosines is \[c^2 = a^2 + b^2 -2ab*cosC\] and the law of sines is \[\frac {sin A}{a} = \frac {sin B}{b} = \frac {sin C}{c}\] where A is the angle of the corner opposite side a, B is the angle of the corner opposite side b, and C is the angle of the corner opposite of side c.

Answer 6

Here's my solution WITHOUT Law of sines or cosines
sine 87° = hgt / 28
sine 87° * 28 = height
height = 0.9986295348 * 28
height = 27.9616269731

x² = 28² - 27.9616269731²
x² = 1.4654068345

15-x = 13.5345931655

f² = hgt² + (15-x)²
f² = 27.9616269731² + 13.5345931655²
f² = 781.8525829828 + 183.1852121556
f² = 965.0377951384
f = 31.0650574623

Answer 7

Thank you one million times over.

Answer 8

Here's a calculator to check the answer:
http://www.1728.org/trig4.htm
It says
side f= 31.065
Angles = 64.171 and 28.829

Answer 9

I've literally been trying to answer this question for the majority of the day. Thanks for your help and the link.

Answer 10

Upper right angle = arc tan (13.5345931655/27.9616269731)
Upper right angle = arc tan (0.4840416897)
Upper right angle = 25.829
Top angle= 3 + 25.829 = 28.829 degrees

Answer 11

Angle G = 180 -28.829 -87
Angle G = 64.171

Answer 12

My way (NOT using law of sines or law of cosines) is a little more work but it shows the work more clearly.