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Mathematics 15 Online
OpenStudy (anonymous):

help! really simple question just a little confused

OpenStudy (anonymous):

is this no solution

OpenStudy (anonymous):

|dw:1408575812736:dw|

OpenStudy (amistre64):

is that sqrt(-13) ??

OpenStudy (anonymous):

lol no its a B

OpenStudy (amistre64):

then there should be some type of solution

OpenStudy (amistre64):

not sure what sqrt(-B) is in the context of what you are trying to accomplish tho

OpenStudy (anonymous):

take a look at this link and you will know what im talking about http://openstudy.com/study#/updates/52d3f31be4b00c91d587902d

OpenStudy (amistre64):

there are no equations on that link

OpenStudy (anonymous):

oh so what that person said is completely wrong?

OpenStudy (amistre64):

now, if the solution set of an equation is spose to be confined to real numbers: then we can form something like:\[\sqrt{x}=-4\]and\[\sqrt{x}=4\] one has a real solution, the other does not

OpenStudy (amistre64):

well, its not completely correct, its only half correct :) in order to make an equation, there has to be an equal sign equating 2 things

OpenStudy (anonymous):

oh ok so in your example would the -4 be the incorrect?

OpenStudy (amistre64):

its not that its incorrect, its just that there is no real solutions defined for it. we have 16i and -16i that are complex solutions to it

OpenStudy (amistre64):

a real number, the word 'real' has a specific meaning in math. its a complex number that has 0 as the imaginary part: r + 0i

OpenStudy (anonymous):

So in the question thats in the link i need to have a radical equation that has a solution and one hat does not have a solution. which one in your example would not have a solution?

OpenStudy (anonymous):

\[\sqrt{16}=4 or \sqrt{-16}=-4\]

OpenStudy (amistre64):

all radical equations have a solution. if we are just focusing on 'real' solutions, then we have to restrict our equations.

OpenStudy (amistre64):

sqrt(16) = 4 + 0i, a real solution since the i part is 0 sqrt(-16) = 0 + 4i, a complex solution since the i part is not 0

OpenStudy (amistre64):

assuming the question is a real solution in context, then sqrt(x) = -4 has no real solution

OpenStudy (amistre64):

sqrt(-x) = 4 has a real solution; x = -16

OpenStudy (amistre64):

library is closing, so ill be leaving in the next 5 minutes or less

OpenStudy (anonymous):

oh ok i think im getting it now. thanks for the the help so if there is somthing i dont understand can i count on you to help me? (:

OpenStudy (amistre64):

if im around, maybe. it all depends on what the something is

OpenStudy (anonymous):

oh ok than in that case i gues this is good bye! thanks for the help(:

OpenStudy (amistre64):

good luck :)

OpenStudy (anonymous):

thank you i will need it lol (:

OpenStudy (anonymous):

oh 1 last question! so do you think i would need to use extranious and non extranious for this question?

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