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If f(x)= x/x-3 and g(x)= 2x -1, find (f-g)(x)
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\(\bf f(x)=\cfrac{x}{x-3}\qquad g(x)= 2x -1 \\ \quad \\ (f-g)(x)\implies f(x)-g(x)\implies \cfrac{x}{x-3}\quad -\quad 2x -1\)
and then what? i got that far but the ending result needs to be a fraction @jdoe0001
yes.... well.. get the LCD and add them up
\(\bf f(x)-g(x)\implies \cfrac{x}{x-3}\quad -\quad 2x -1\implies \cfrac{x}{x-3}\quad -\quad \cfrac{2x}{1}-\cfrac{1}{1}\) got LCD?
ugh no. is it x-3 or is it 1
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or none of those
hmmm well.... is a "value you can divide all those by" so in short , if not found quickly you can always just multiply them all and and that'd be the LCD so \(\bf (x-3)\cdot 1\cdot 1\implies 1(x-3)\implies (x-3)\)
i got it thanks! :)
yw
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