If f(x)= x/x-3 and g(x)= 2x -1, find (f-g)(x)

Question

jdoe0001 · Answer

$\bf f(x)=\cfrac{x}{x-3}\qquad g(x)= 2x -1
\ \quad \
(f-g)(x)\implies f(x)-g(x)\implies \cfrac{x}{x-3}\quad -\quad 2x -1$

anonymous · Answer

and then what? i got that far but the ending result needs to be a fraction @jdoe0001

jdoe0001 · Answer

yes.... well.. get the LCD and add them up

jdoe0001 · Answer

$\bf  f(x)-g(x)\implies \cfrac{x}{x-3}\quad -\quad 2x -1\implies \cfrac{x}{x-3}\quad -\quad \cfrac{2x}{1}-\cfrac{1}{1}$   got LCD?

anonymous · Answer

ugh no. is it x-3 or is it 1

anonymous · Answer

or none of those

jdoe0001 · Answer

hmmm well....  is a "value you can divide all those by"
so in short , if not found quickly
you can always just multiply them all and and that'd be the LCD  so $\bf (x-3)\cdot 1\cdot 1\implies 1(x-3)\implies (x-3)$

anonymous · Answer

i got it thanks! :)

jdoe0001 · Answer

yw