Factor 4a^2-8ab-3a+6b
@jim_thompson5910
Re-write as: 4a^2 - 3a - 8ab + 6b (This is legal because of the commutative property) Next factor the first two terms, then the last two terms. If you need help let me know.
Do you mean like (4a^2-3a)(-8ab+6b)? @Hero
Well, no because 4a^2 - 3a - 8ab + 6b is not equivalent to (4a^2-3a)(-8ab+6b). Factoring implies using the distributive property to express terms as a multiplication of prime factors.
In this case, process involves finding numbers or variables that are common to each term and extracting them from the original expression.
So a for the first one and 2b for the second?
Close... a for the first one and -2b for the second.
okay, so how would I write that? a(4a-3)-2b(4a-3)?
Nice. Now, notice that 4a-3 is common to each factorization. So you have to factor that out as well.
how?
let c = 4a - 3 then you have ac - 2bc Factor ac - 2bc
c(a-2b) so it's (4a-3)(a-2b)? I think....?
Correct
Thanks! It's been a while since I've done factoring like this and I just started a new math class that is technically a lower level than my prerequisites... It's just college level instead of High School
You're welcome. Good luck with everything.
Thanks!
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