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Mathematics 8 Online
OpenStudy (anonymous):

Factor 4a^2-8ab-3a+6b

OpenStudy (anonymous):

@jim_thompson5910

hero (hero):

Re-write as: 4a^2 - 3a - 8ab + 6b (This is legal because of the commutative property) Next factor the first two terms, then the last two terms. If you need help let me know.

OpenStudy (anonymous):

Do you mean like (4a^2-3a)(-8ab+6b)? @Hero

hero (hero):

Well, no because 4a^2 - 3a - 8ab + 6b is not equivalent to (4a^2-3a)(-8ab+6b). Factoring implies using the distributive property to express terms as a multiplication of prime factors.

hero (hero):

In this case, process involves finding numbers or variables that are common to each term and extracting them from the original expression.

OpenStudy (anonymous):

So a for the first one and 2b for the second?

hero (hero):

Close... a for the first one and -2b for the second.

OpenStudy (anonymous):

okay, so how would I write that? a(4a-3)-2b(4a-3)?

hero (hero):

Nice. Now, notice that 4a-3 is common to each factorization. So you have to factor that out as well.

OpenStudy (anonymous):

how?

hero (hero):

let c = 4a - 3 then you have ac - 2bc Factor ac - 2bc

OpenStudy (anonymous):

c(a-2b) so it's (4a-3)(a-2b)? I think....?

hero (hero):

Correct

OpenStudy (anonymous):

Thanks! It's been a while since I've done factoring like this and I just started a new math class that is technically a lower level than my prerequisites... It's just college level instead of High School

hero (hero):

You're welcome. Good luck with everything.

OpenStudy (anonymous):

Thanks!

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