Question

x^c+3 times x^c-3

Answer 1

\(\ \Large \sf x^y * x^y = x^{y + y} = x^{2y} \)

That being said,

\(\ \sf \Large x^{(c + 3)} \times x^{(c -3)} \implies x^{(c + 3 + c - 3)} \implies x^{\color{red}{c} \color{green}{+3} \color{red}{+ c} \color{green}{-3}} = x^{2\color{red}{c}}\)

Answer 2

Oh that fail... \(\ \Large x^{(c + 3)} * x^{(c- 3)} \) There :3 Less confusing ~

Answer 3

... Amusing that is wasn't \(\ \sf (x^c + 3) * (x^c - 3) \)

Answer 4

Let me ask you,

How much is
\[2^{4} \times 2^{3}\]
The fourth power of 2 is 16; the third power is 8.

16 times 8 = 128

We could have added the exponents
\[2^{4} \times 2^{3} = 2^{7}\]

Now, do the same thing with your problem:

\[x^{(c+3)} * x^{(c-3)} = x^{?}\]
What do you get when you add (c+3) plus (c-3)?

Change the question mark above, and you get:
\[x^{(c+3)} * x^{(c-3)} = x^{2c}\]
I hope this was helpful.

Answer 5

u understood this?