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how to find the slope of the line if the equation is in standard form
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Ax+By+C=0, slope = -A/B
Yes because Standard form is \(Ax+By+C=0\). Rearranging it for y to put it in slope-y-intercept form yields: \[Ax+By+C=0 \\ By=-Ax-C \\ y=-\frac{A}{B}x-\frac{C}{B}\] And since we know the slope of any formula with the equation \(y=mx+b\) is \((m)\), then we know that the slope of \(y=-\frac{A}{B}x-\frac{C}{B}\) is \((-\frac{A}{B})\)
THe general form of an equation of a line is y = mx + c Slope , m = -y/m
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