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Mathematics 6 Online
OpenStudy (anonymous):

sin and cosine work, please help?

OpenStudy (anonymous):

\[\sin^2 \alpha+ \cos^2 \alpha =\]

OpenStudy (anonymous):

Should equal 1

OpenStudy (imstuck):

This is an identity that is pretty popular. Do you know it?

OpenStudy (anonymous):

identities arent my best, but im here or there on info about them.

OpenStudy (anonymous):

How does it equal one? or do you know where i can find a good identity chart or set of rules?

OpenStudy (anonymous):

It equals one simply because of the rule that's given, and as it is an important rule, you'll want to know it. We know it's true because we are told so.

OpenStudy (anonymous):

You should check out some Unit Circles to understand why it equals to one

OpenStudy (xapproachesinfinity):

no there is a reason why it is 1 it is the Pythagorean thm using trig function in the unit circle

OpenStudy (anonymous):

|dw:1408590173108:dw|

OpenStudy (anonymous):

example ^^^^^

OpenStudy (xapproachesinfinity):

|dw:1408590195784:dw|

OpenStudy (anonymous):

Ah... thanks pal,

OpenStudy (xapproachesinfinity):

okay now from that triangle we have x^2+y^2=r^2 but r is just 1 so x^2+y^2=1, yes?

OpenStudy (xapproachesinfinity):

welcome bro^_^

OpenStudy (xapproachesinfinity):

that equation is know as circle equation in the unit circle

OpenStudy (anonymous):

Haha um, thank you all for the help of understanding this, a bit more. I understand that this identity equals 1 and i have to get the rest of the rules down, thank you all for the help.

OpenStudy (xapproachesinfinity):

|dw:1408590451736:dw|

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