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Mathematics 11 Online
OpenStudy (anonymous):

Part A: Using the graph above, create a system of inequalities that only contain points C and F in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (5 points) Part B: Explain how to verify that the points C and F are solutions to the system of inequalities created in Part A. (3 points) Part C: Natalie can only attend a school in her designated zone. Natalie's zone is defined by y < -2x + 2. Explain how you can identify the schools that Natalie is allowed to attend. (2 points)

OpenStudy (anonymous):

OpenStudy (anonymous):

@Cacciatore_J plz plz help me

OpenStudy (anonymous):

Of course

OpenStudy (anonymous):

lol ty ty ^-^ your the only smart guy i know

OpenStudy (anonymous):

A) Your primary concerns are the points B and E, so y> .5x+4 and y>or= x-4

OpenStudy (anonymous):

B) choose one or both points, and enter them into the equations. If the statements are true, then the equations work

OpenStudy (anonymous):

the only points for part a is c and f

OpenStudy (anonymous):

sorry i meant to tell that >.<

OpenStudy (anonymous):

No problem, as for C, simply place a point into the equation, as with B). If they work, then those schools are available to Natalie

OpenStudy (anonymous):

ok sorry i dont mean to wast you time but can u kinda write that all down for me im really sorry

OpenStudy (anonymous):

like from aband c if its no trouble

OpenStudy (anonymous):

A) y> -1/2x + 4 and y > or = -x + 4

OpenStudy (anonymous):

On moment, let me double check some stuff

OpenStudy (anonymous):

ok ^-^

OpenStudy (anonymous):

For C: y >= -x +4 -> 2>=-2+4 which works

OpenStudy (anonymous):

For A) I confused an eq. y>-2x+4 rather than -.5x+4

OpenStudy (anonymous):

So, for C: y>-2x+4 -> 2>-4+4, so that's true, too

OpenStudy (anonymous):

oh ok so just like u had made for c that excatly what i say in my equation?

OpenStudy (anonymous):

For F: y>/=-x+ 4 -> 4>/=-3+4 y>-2x+4 -> 4>-6+4 So both equations work for F, and thusare both valid equations All of that was for part B)

OpenStudy (anonymous):

C)

OpenStudy (anonymous):

oh ok thank you ^-^ now all i have is c then i be done and thx btw for taking the time to help me ^-^

OpenStudy (anonymous):

No problem

OpenStudy (anonymous):

The attached file shows the graph of the equation for problem C So, any point in the shaded area, but not on the line, are valid points for Natalie's school

OpenStudy (anonymous):

Does that make sense?

OpenStudy (anonymous):

yea oh ok so thats gotta say to part c

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Bingo, but make sure, for C) that the "shaded area" is clarified as the area less than the given equation.

OpenStudy (anonymous):

No problem, but why not delete this thread?

OpenStudy (anonymous):

its my flvs teacher they have a thing other teachers go on the internet to see if they got things on the internet

OpenStudy (anonymous):

If you wait a while, I believe bumping is how you delete a thread. I'm new, so I couldn't tell you, though

OpenStudy (anonymous):

oh ok but is it if coud if i get cuaght again im dead lol sorry i dont mean to be annoying lol

OpenStudy (anonymous):

cool picture ^-^

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