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Mathematics 7 Online
OpenStudy (anonymous):

Assistance with making a function that gives the direction with point (3,0) to a point on the unit circle.

OpenStudy (imstuck):

I don't understand. Are you needing to write a function from point (3,0) to a point on the unit circle?

OpenStudy (anonymous):

ill write it word for word

OpenStudy (imstuck):

I really hope this isn't vectors...

OpenStudy (anonymous):

define a funtion that gives the ditance from the point P(3,0) to a point on the unit circle. state domain and range of this funtion

OpenStudy (anonymous):

im dealing with this and im only on day 2 of calc AB D:

OpenStudy (imstuck):

Oh, I think I got that. Maybe. The unit circle is a circle with a radius of 1 all around.

OpenStudy (anonymous):

yes i was trying to get point (1,0)

OpenStudy (imstuck):

|dw:1408598804995:dw|

OpenStudy (anonymous):

but i cant think of a funtion that gets me (1,0) AND (3,0)

OpenStudy (imstuck):

From point (3,0) you have this:

OpenStudy (imstuck):

|dw:1408598870357:dw|

OpenStudy (anonymous):

isnt that a tangent line though

OpenStudy (anonymous):

or are my eys failing me

OpenStudy (imstuck):

Yes, it is. But isnt the line supposed to just touch on the unit circle?

OpenStudy (imstuck):

that is a tangent line

OpenStudy (anonymous):

it siad to a point on a unit circle

OpenStudy (anonymous):

tangents dont necesaily touch it right?

OpenStudy (imstuck):

a point on the unit circle will be a tangent line. It' ON the circle not INSIDE the circle. Tangents most definitely DO touch it.

OpenStudy (anonymous):

Ah kk

OpenStudy (imstuck):

So we need to find an equation for that line. We could have drawn the line to the lower half of the circle, but I just picked the upper half.

OpenStudy (anonymous):

how would we go about doing that

OpenStudy (imstuck):

It doesn't even have to touch there.

OpenStudy (imstuck):

It could look like this, which might actually be easier:

OpenStudy (imstuck):

|dw:1408599160194:dw|

OpenStudy (imstuck):

Or even simpler:

OpenStudy (anonymous):

mind telling me how u do those things and how u get the functions for them?

OpenStudy (imstuck):

|dw:1408599255783:dw|

OpenStudy (anonymous):

nvm i figured

OpenStudy (imstuck):

Ok if you extend that line out it would intercept the y axis at 1 with a slope of -1/3. So the equation is y = -1/3x + 1

OpenStudy (anonymous):

Ah thank you so much

OpenStudy (imstuck):

|dw:1408599390135:dw|

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