Joining the frequent visitor program at the planetarium costs $5 per year, Write an equation that can be used to determine n, the number of visits per year for which the cost of being a member of the frequent visitor program is equal to the cost of not being a member. Tickets cost $11 for each student who is a member of the planetarium's frequent visitor program and $13 for each student who is not a member. @terenzreignz Plz help! I heard you were smart :)
This question is really confusing to me and I ask others and they said the same too, I'm not sure how to do this and how I'm gonna get this done >.>
Who told you that? D:
I only have one more hr, then I have to to get ready for school >.>
@terenzreignz do you know how to do this? >.>
I'm reading... hang on.
Ok :)
Teren o-o
Okay... if you're a member, how much does it cost to pay n-visits?
If I'm a member I pay the cost of $11 instead of the nonmember cost of $13
So
I could represent the visits by 11
11n
11n yes, but you also have to pay the membership :)
11n +5y?
y for years
Just 5. The problem says "per year" so it's just one year. thus..?
11n + 5 = 13n?
Very good... are you sure you really needed me for this? haha
I don't get it, that's how far I got v-v
I used the formula, solved for it, and I didn't know what to do after that >.>
It just says write an equation.
Yeah that is problem 13. Problem 14 says: Solve your equation from item 13. List a property of equality or provide an explanation for each step Problem 15: Explain the meaning of the solution of the equation Problem 16: Nash plans to visit the planetarium twice in the next year. Should he join the frequent visitor program? Explain
In Problem 14 I solved for the equation and I got y = 0.4
I had used 5y + 11n = 13n
I thought I needed the y >.>
@terenzreignz So I don't need the y?
Not at all.
Ok hold on, I'm gonna redo problem 14 :P
Ok so n = 2.5 ???
It would seem so... :/
n was the number of visits per year...what does it mean when the number of visits was 2.5? o-o
Yes... impossible, right? :/
Is the equation wrong or something?
No... I don't think so, at least.
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