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In how many ways can the letters P R O B A B I L I T I E S be arranged (a) without any other restrictions? (b) such that the E and the A appear next to each other? (c) such that the E and the A does not appear next to each other?
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I think the answer to a is \[\frac{ 13! }{ 2! 3!}\]
(a) is correct
:)
For b I get \[\frac{ 12! }{ 2!3! }\times2!\]
Yep, (b) is also right
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Yay, thanks!
And for c, I did the answer for a - the answer for b.
Sounds reasonable. Good work!
Alright! Thanks so much!
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