Mathematics
15 Online
OpenStudy (anonymous):
What is the length of AB?
Pic below, It will be a square root.
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
11 years ago
OpenStudy (phi):
can you make a right triangle?
11 years ago
OpenStudy (anonymous):
Yeah...
11 years ago
OpenStudy (phi):
drop a line straight down. then over.
find the length of each side (count "boxes" )
then use a^2 + b^2 = c^2
11 years ago
OpenStudy (princeharryyy):
sqrt((4-1)^2-(3-2)^2)
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I know the pythagorean theorem...
11 years ago
OpenStudy (anonymous):
I would use 3 and 1, right?
11 years ago
OpenStudy (phi):
then you should see you have a width of 1 and height of 3
11 years ago
OpenStudy (princeharryyy):
sqrt(10)
11 years ago
OpenStudy (anonymous):
Yeah Phi.
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So 1^2=1 and 3^2=9
11 years ago
OpenStudy (phi):
yes, add together and you have c^2
take the square root to get c
11 years ago
OpenStudy (anonymous):
10^2=100, but the answer is 10?
11 years ago
OpenStudy (phi):
slow up
a^2 + b^2 = c^2
1 + 9= c^2
10 = c^2
11 years ago
OpenStudy (anonymous):
Oh so I need the square root of ten?
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (phi):
yes
11 years ago
OpenStudy (anonymous):
3.1?
11 years ago
OpenStudy (anonymous):
Or 100?
11 years ago
OpenStudy (phi):
unless they want decimals I would leave it
\[ \sqrt{10} \]
that is exact. (If someone want to get the approximate answer, they can use a calculator)
11 years ago
OpenStudy (anonymous):
Okay! ^.^ Thanks for your help!
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (phi):
\[ c^2 = 10 \\ \sqrt{c^2} = \sqrt{10} \\ c = \sqrt{10} \]
11 years ago
OpenStudy (phi):
notice if you squared both sides you would be doing this
\[ c^2 = 10 \\ \left(c^2\right)^2 = \left(10\right)^2 \\ c^4= 10^2 \]
which is not what we want
11 years ago
OpenStudy (anonymous):
Yeah, I get that.
11 years ago