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Mathematics 15 Online
OpenStudy (anonymous):

What is the length of AB? Pic below, It will be a square root.

OpenStudy (anonymous):

OpenStudy (phi):

can you make a right triangle?

OpenStudy (anonymous):

Yeah...

OpenStudy (phi):

drop a line straight down. then over. find the length of each side (count "boxes" ) then use a^2 + b^2 = c^2

OpenStudy (princeharryyy):

sqrt((4-1)^2-(3-2)^2)

OpenStudy (anonymous):

I know the pythagorean theorem...

OpenStudy (anonymous):

I would use 3 and 1, right?

OpenStudy (phi):

then you should see you have a width of 1 and height of 3

OpenStudy (princeharryyy):

sqrt(10)

OpenStudy (anonymous):

Yeah Phi.

OpenStudy (anonymous):

So 1^2=1 and 3^2=9

OpenStudy (phi):

yes, add together and you have c^2 take the square root to get c

OpenStudy (anonymous):

10^2=100, but the answer is 10?

OpenStudy (phi):

slow up a^2 + b^2 = c^2 1 + 9= c^2 10 = c^2

OpenStudy (anonymous):

Oh so I need the square root of ten?

OpenStudy (phi):

yes

OpenStudy (anonymous):

3.1?

OpenStudy (anonymous):

Or 100?

OpenStudy (phi):

unless they want decimals I would leave it \[ \sqrt{10} \] that is exact. (If someone want to get the approximate answer, they can use a calculator)

OpenStudy (anonymous):

Okay! ^.^ Thanks for your help!

OpenStudy (phi):

\[ c^2 = 10 \\ \sqrt{c^2} = \sqrt{10} \\ c = \sqrt{10} \]

OpenStudy (phi):

notice if you squared both sides you would be doing this \[ c^2 = 10 \\ \left(c^2\right)^2 = \left(10\right)^2 \\ c^4= 10^2 \] which is not what we want

OpenStudy (anonymous):

Yeah, I get that.

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