A pilot wishes to fly from Bayfield to Kitchener, a distance of 100 km on a bearing of 105°. The speed of the plane in still air is 240 km/h. A 20 km/h wind is blowing on a bearing of 210°.
Remembering that she must fly on a bearing of 105° relative to the ground (ie the resultant must be on that bearing), find
the heading she should take to reach her destination
how long will the trip take
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OpenStudy (anonymous):
@JoannaBlackwelder
OpenStudy (anonymous):
@asnaseer
OpenStudy (anonymous):
@Luigi0210
OpenStudy (joannablackwelder):
I would start by adding the velocity vectors here, I think. Can you find the resultant speed?
OpenStudy (anonymous):
Why?
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OpenStudy (joannablackwelder):
Hm, hold on. I am still working on it....
OpenStudy (anonymous):
Okay Thanks same here!
OpenStudy (joannablackwelder):
I found the resultant magnitude by law of cosines.
OpenStudy (joannablackwelder):
But I haven't yet found the angle.
OpenStudy (joannablackwelder):
I think I can get it using summing the x components and y components and using trig ratios, but I have to go. Sorry!
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OpenStudy (joannablackwelder):
I'll be back on later today.
OpenStudy (joannablackwelder):
You can use rate=distance*time to find time once you have rate.