Can someone help meh with a question :D

A system of equations is shown below:

3x + 8y = 12
2x + 2y = 3

Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points)

Part B: Show that the equivalent system has the same solution as the original system of equations. (4 points)

Question

Can someone help meh with a question :D

A system of equations is shown below:

3x + 8y = 12
2x + 2y = 3

Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points)

Part B: Show that the equivalent system has the same solution as the original system of equations. (4 points)

anonymous · Answer

@BetterOffLearningThenNot

anonymous · Answer

Yo

anonymous · Answer

That'd be great. I'm just not the best at equations... Just tryin' to get this question done so i can go eat xD

anonymous · Answer

*paste

anonymous · Answer

and then click the first one

anonymous · Answer

I tried that... Didnt really help. Sorry... I'm sort of simple minded when it comes to Algebra.

anonymous · Answer

oh maybe zpupster can help

anonymous · Answer

sorry i could not help @BetterOffLearningThenNot

anonymous · Answer

:(

anonymous · Answer

Oh right. I remember... Alrighty. Just tell me what to do.. And i hope i can solve it.

anonymous · Answer

Oh its totally okay man! Hey aleast you tried thats what counts.

anonymous · Answer

I'm just confused when i try to do it. For some reason...

anonymous · Answer

I don't really know how you got to that point in the question there...

anonymous · Answer

Multiply the first equation by -2$$-6x-16y=-24$$
then the bottom equation by 3$$6x+6y=9$$

anonymous · Answer

But... How did you get the -2 to devide by... This is what im stumped on.

anonymous · Answer

Whoops multiply by.

anonymous · Answer

You need a negative number to cancel out a positive number. So think of the LCM of 3 and 2. It would be 6. In order to get six you have to multiply a positive number to one equation  and a negative number to the second equation so they can cancel out.

anonymous · Answer

Yeah... But why does it have to be positive? Will the equation be un-solvable if its not positive?

anonymous · Answer

Yes because if it was positive, you would not be able to cancel out the "x" variable in the equation. When you cancel out the x you will be able to find out what "y" is $$-16y +6y=-24+9$$

anonymous · Answer

OKay. So... This is getting closer to our answer huh? Yeah sorry, I'm not good at math really XD

anonymous · Answer

It's okay haha, but yea so after you get "y" all you have to do is plug it in one of the original equations and then you will have the answer for "x"

anonymous · Answer

Okay, So ima re paste this so we can answer the question... 

A system of equations is shown below:

3x + 8y = 12
2x + 2y = 3

Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points)

Part B: Show that the equivalent system has the same solution as the original system of equations. (4 points)

anonymous · Answer

What would we have to do for part A?

anonymous · Answer

I think it would be easier to start out with canceling out the "y" variable so multiply the second equation by -4 $$-8x-8y=-12$$ so after the -8y and 8y cancel out you end with $$3x-8x=12-12$$

anonymous · Answer

$$-5x=0$$ should be your answer and then add 5 to the other side . x=5

anonymous · Answer

This would be part a

anonymous · Answer

Then plug 5 into the x variable in both equations and solve them$$3(5)+8y=12$$ $$2(5)+2y=3$$

anonymous · Answer

part b

anonymous · Answer

Okay.... Thanks so much for helping meh

anonymous · Answer

No problem

anonymous · Answer

So we got both parts here? Can you summarize it real quick for me? Just so i know wha to put for the answer?