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Mathematics 21 Online
OpenStudy (anonymous):

Question 1 : Signals : Represent the following functions in terms of g(t).. (Diagrams in comments)..

OpenStudy (anonymous):

Plus, I am not good at drawing.. :)

OpenStudy (amistre64):

signals, like heaviside functions

OpenStudy (anonymous):

|dw:1408644929638:dw|

OpenStudy (anonymous):

Sorry, you have to wait that long for this question..

OpenStudy (anonymous):

And WAIT, WAIT, WAIT, I have my answer with me.. I need your favor in checking that.. :)

OpenStudy (anonymous):

\[f(t)=\begin{cases}4&\text{for }0\le t<1\\3&\text{for }1\le t<2\\2&\text{for }2\le t<3\\1&\text{for }3\le t<4&\text{or maybe }\le4\text{, doesn't seem to matter}\end{cases}\] and \[g(t)=\begin{cases}1&\text{for }-1\le t\le1\\0&\text{otherwise}\end{cases}\] Is this right?

OpenStudy (anonymous):

\[f(t) = g(\frac{1}{2}t - 1) + g(\frac{2}{3}t - 1) + g(t - 1) + g(2t - 1)\]

OpenStudy (anonymous):

Yes, and after 4 it is 0..

OpenStudy (anonymous):

I mean for \(t > 4\), \(f(t) = 0\)..

OpenStudy (amistre64):

hmm, well we can make an actual switch: g(t) = -(t^2-1)/(2|t^2-1|)+1/2

OpenStudy (anonymous):

|dw:1408645621228:dw||dw:1408645637970:dw| Seems like all you need is a few \(g(2t-1)\) terms, each with a scalar and the appropriate shift.

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