Question

intergal of 3x^5 sin(x^3)dx

Answer 1

\[\int\limits_{}^{}3x^5 \sin(x^3) dx\]

Answer 2

i chose u= sin(x^3) dv= 3x^5

Answer 3

you should :
let t = x^3 --> dt = 3x^2 dx
and \(x^5 = x^2x^3\)
\[\rightarrow \int t~sin~t~ dt\]

Answer 4

now, take it by parts by letting u =t and dv = sint dt

Answer 5

i got du= 3x^2 cos(x^3) dx

Answer 6

v= 1/2 x^6

Answer 7

you got stuck when the exponent of x is bigger and bigger if you go on that way

Answer 8

oh no wonder it keep going forever

Answer 9

Try my way!! :)

Answer 10

happend to 3x^5?

Answer 11

\(x^5 =x^{3+2}=x^3*x^2\)

Answer 12

oooooooooooooooo

Answer 13

what does oooooooooooooooo mean?

Answer 14

'oh' lol

Answer 15

got it now, right? :)

Answer 16

let me try :D

Answer 17

so for 3 i bring it out side?

Answer 18

nope, let t = x^3 --> dt = 3x^2 dx
"3" is used here--> no need to move it out