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Mathematics 21 Online
OpenStudy (anonymous):

Can someone help me answer these questions please and thank you

OpenStudy (anonymous):

OpenStudy (imstuck):

First determine what the coordinates of the center of the circle are. What are they?

OpenStudy (imstuck):

Point K is the center; what are its coordinates? In the form (x, y)

OpenStudy (anonymous):

(4,3)

OpenStudy (anonymous):

@IMStuck

OpenStudy (imstuck):

Yes ok. Good. Do you know the general equation for a circle? The formula for a circle?

OpenStudy (anonymous):

A=pi *r^2

OpenStudy (imstuck):

No, that's the area formula. The general equation for a circle is this:\[(x-h)^{2}+(y-k)^{2}=r ^{2}\]

OpenStudy (imstuck):

h is the x coordinate for the center and k is the y coordinate for the center.

OpenStudy (imstuck):

Does that look familiar to you?

OpenStudy (imstuck):

Are you with me on this?

OpenStudy (anonymous):

so i would put it as (x-3)^2 + (y-4)^2 = r^2

OpenStudy (anonymous):

@IMStuck

OpenStudy (anonymous):

so my internet was down

OpenStudy (imstuck):

Ok, that's fine. I'm back. Let me check your equation so far. BRB

OpenStudy (anonymous):

oki

OpenStudy (imstuck):

Ok, here's the thing. First of all, your x coordinate for the center is 4 and the y is 3. You had them reversed in your equation. Also, you need to make the numbers fit into the formula of \[(x-h)^{2}\]and \[(y-k)^{2}\]In order to do that, take your x coordinate of 4 and plug it in in this way:

OpenStudy (imstuck):

\[(x-(4))^{2}\]which is, of course, just \[(x-4)^{2}\]The same goes for the y, which is a -3 and needs to fit into the equation like this:

OpenStudy (imstuck):

\[(y-(-3))^{2}\]which translates to \[(y+3)^{2}\]

OpenStudy (imstuck):

I think originally you had the coordinates for the center as (4,3) and they are actually (4,-3).

OpenStudy (anonymous):

oh so it would be (x-4)^2 + (y-(-3))^2 =r^2

OpenStudy (imstuck):

So far it would be \[(x-4)^{2}+(y+3)^{2}=r ^{2}\]

OpenStudy (imstuck):

Now we have to worry about the r, which is the radius. Do you know how to find the radius from the image?

OpenStudy (anonymous):

no i don't

OpenStudy (anonymous):

sorry math isn't really my subject lol

OpenStudy (imstuck):

Ok your circle has a center of K. If you count the units up from K to the point on the brown outline of the circle, how many units did you go up? How many squares?

OpenStudy (anonymous):

5

OpenStudy (imstuck):

Yes, and that is exactly half the diameter of the circle, which is another name for radius! Now we take that radius of 5 and square it. What is 5^2?

OpenStudy (imstuck):

What is 5 times 5?

OpenStudy (anonymous):

10

OpenStudy (imstuck):

That is 5 times 2. What is 5 times 5? That is what it means when it wants "5 squared". 5 times 5.

OpenStudy (imstuck):

we are at the last step here, don't get upset, ok? You're doing great!

OpenStudy (anonymous):

oh my bad i misread it and its 25

OpenStudy (imstuck):

Yes, so now we have completed the circle's equation, and it is:\[(x-4)^{2}+(y+3)^{2}=25\]

OpenStudy (anonymous):

thank you now can you help me find the questions on the side ?

OpenStudy (anonymous):

@IMStuck

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