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OpenStudy (jdoe0001):
hmmm have you covered logarithms yet?
OpenStudy (anonymous):
yes but it was so long ago i dont remember . i know it can be converted to natural log
OpenStudy (joannablackwelder):
Is it \[\frac{ 5 }{ e ^{x} +1}=1\]
OpenStudy (anonymous):
yes !
OpenStudy (joannablackwelder):
Ok. First get x in the numerator by multiplying by the denominator on both sides.
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OpenStudy (joannablackwelder):
That leaves us with.
\[5=e ^{x}+1\]
OpenStudy (joannablackwelder):
Following me so far?
OpenStudy (anonymous):
did you cross multiply ?
OpenStudy (joannablackwelder):
That is one way to describe it. :)
OpenStudy (anonymous):
okay i understand then , continue ?
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OpenStudy (joannablackwelder):
Good. Now, continue working on isolating x by subtracting 1 on both sides.
OpenStudy (joannablackwelder):
Can you tell me what that leaves us with?
OpenStudy (anonymous):
[5-1=e^{x}\]
OpenStudy (joannablackwelder):
Right or
\[4=e ^{x}\]
OpenStudy (anonymous):
yeah sorry about the brackets
so do we have to convert to natural log ?
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OpenStudy (joannablackwelder):
No worries. Yes, take the natural log of both sides.
OpenStudy (joannablackwelder):
What did you get?
OpenStudy (anonymous):
does e = ln ?
OpenStudy (joannablackwelder):
No, but ln(e^x)=x
Natural log cancels out e^
OpenStudy (anonymous):
is there a rule to use any time you're converting from e to ln or ln to e ?
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OpenStudy (joannablackwelder):
I'm using the idea that ln(e)=1
OpenStudy (anonymous):
im confused on how you convert then . how can you go from e^x to ln if when you times them they equal 1 ?
OpenStudy (anonymous):
i understand you up to this point :(
OpenStudy (joannablackwelder):
Just a sec.
OpenStudy (xapproachesinfinity):
well one way to think about it is that lnx and e^x are inverse of each other
fo f(g(x))=x comes in handy here
whether you do this ln(e^x)=x or e^(lnx)=x you always end up with the identity function x
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OpenStudy (joannablackwelder):
My bad. I gave you the wrong property. It should be
\[\log _{b}b ^{x}=x\]
OpenStudy (joannablackwelder):
So that brings us to ln4=x :)
OpenStudy (xapproachesinfinity):
lne=1 since e^1=e. you always thing of log and exponential as inverses
in other words they undo each other
OpenStudy (xapproachesinfinity):
you can also rewrite to make it more funcy
2ln2=x
do you know what property is this?
OpenStudy (anonymous):
why are there two b's in joannas formula ? and no i dont
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OpenStudy (xapproachesinfinity):
that logarithms base b
ln is logar base e
OpenStudy (joannablackwelder):
The base and what you are taking the log of are the same.
OpenStudy (joannablackwelder):
Natural log is log base e.
OpenStudy (xapproachesinfinity):
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now think of this power that has base 2
OpenStudy (xapproachesinfinity):
we went from 2 to the power of 3=8
log helps us to undo this powering if u may say
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