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Mathematics 6 Online
OpenStudy (anonymous):

write the equation of a function h(t) that represents the amount of heat in joules required to heat the bar to a temp of t degrees Celsius

OpenStudy (anonymous):

OpenStudy (anonymous):

@jdoe0001 @Nnesha

OpenStudy (jdoe0001):

hmm what did the table give you?

OpenStudy (jdoe0001):

usually the Joules and Celsius made could just be used as an "x" and "y" table with each pair being a coordinate of the graph so you'd do the same as before to get the equation, pick 2 points, get their slope and then plug in the point-slope form

OpenStudy (anonymous):

|dw:1408659045226:dw|

OpenStudy (jdoe0001):

hmmm well... the gold bar was 25 degrees warm from the getgo to raise it to 26 you'd just need 7Joules so would be more like \( \bf \begin{array}{ccllll} Joules&Celsius \\\hline\\\ x&y \\\hline\\ 7&26\\ {\color{red}{ 14}}&{\color{blue}{ 27}}\\ 21&28\\ {\color{red}{ 28}}&{\color{blue}{ 29}}\\ 35&30 \end{array} \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 14}}\quad ,&{\color{blue}{ 27}})\quad &({\color{red}{ 28}}\quad ,&{\color{blue}{ 29}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)

OpenStudy (anonymous):

slope is 7 y=7x-168

OpenStudy (anonymous):

o nevermind, you used joules as x not y give me a sec

OpenStudy (jdoe0001):

keep in mind that Joules is the INPUT, and the Celsius is the OUTPUT

OpenStudy (anonymous):

wait your graph is wrong

OpenStudy (jdoe0001):

hmm.... where is it off?

OpenStudy (anonymous):

x is 14 and y is 26 not x is 7

OpenStudy (jdoe0001):

hmmm ok...... x = 14 means 2 Celsius or 7 + 7 Joules starting off at 25 degrees warm, the gold bar will go up to 27

OpenStudy (anonymous):

o ok, i see. so it doesnt start with 7, 25 because nothings been heated its just 0,25

OpenStudy (jdoe0001):

yeap

OpenStudy (anonymous):

so slope is still 7

OpenStudy (anonymous):

y=7x-175?

OpenStudy (anonymous):

how do i put that in the h(t) thing?

OpenStudy (jdoe0001):

hmm site is getting laggy

OpenStudy (jdoe0001):

\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 14}}\quad ,&{\color{blue}{ 27}})\quad &({\color{red}{ 28}}\quad ,&{\color{blue}{ 29}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ 29}}-{\color{blue}{ 27}}}{{\color{red}{ 28}}-{\color{red}{ 14}}}\implies ?\)

OpenStudy (anonymous):

2/14 or 1/7

OpenStudy (jdoe0001):

yeap thus \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 14}}\quad ,&{\color{blue}{ 27}})\quad &({\color{red}{ 28}}\quad ,&{\color{blue}{ 29}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{1}{7} \\ \quad \\ y-{\color{blue}{ 27}}={\color{green}{ \cfrac{1}{7}}}(x-{\color{red}{ 14}})\qquad \textit{plug in the values }\\ \qquad \uparrow\\ \textit{point-slope form} \)

OpenStudy (jdoe0001):

it doesn't need it in any specific form... so I gather point-slope form is just as good

OpenStudy (anonymous):

ok, what about #12?

OpenStudy (jdoe0001):

he/she 's buying cases of balls, each case has 24 cans, each can 24 balls the INPUT here is how many cases? the OUTPUT is how many balls? well... in 1 case there are 24* 3 balls so there \(\large \begin{array}{rrrllll} cases&balls \\\hline\\ 1&24\cdot 3\to 72\\ 2&144\\ 3&288\\ 4&576\\ ...&... \end{array}\) pick any 2 points, get the "x" and "y" and get their slope and same as before plug in the point-slope form

OpenStudy (jdoe0001):

woops he/she 's buying cases of balls, each case has 24 cans, each can 3 balls thus 24 * 3

OpenStudy (anonymous):

slope is 72

OpenStudy (anonymous):

y=72x?

OpenStudy (anonymous):

|dw:1408661668227:dw|

OpenStudy (jdoe0001):

hmmm right my table is a bit off there.... but yes... that's correct should be \(\begin{array}{rrrllll} cases&balls \\\hline\\ 1&24\cdot 3\to 72\\ 2&144\\ 3&288\\ 4&360\\ ...&... \end{array}\) anyhow

OpenStudy (jdoe0001):

yeap

OpenStudy (anonymous):

so how would i graph that with no y-intercept

OpenStudy (jdoe0001):

you forgot about our good fellow Mr Zero \(\large \begin{array}{llll} y=&{\color{brown}{ 72}}x&{\color{blue}{ +0}}\\ &\uparrow &\uparrow \\ &{\color{brown}{ slope}}&{\color{blue}{ y-intercept}} \end{array}\)

OpenStudy (anonymous):

o ok :) what does the slope represent in the function? the number of cans in a case?

OpenStudy (jdoe0001):

slope is a rate of change how much is "y" changing on every change in "x"

OpenStudy (jdoe0001):

so.... in this case... "y" is how many balls in each "x" cases

OpenStudy (anonymous):

that would mean there are 7 balls in each case :/

OpenStudy (jdoe0001):

yes IF the slope were 7, yes

OpenStudy (anonymous):

well if our slope is 1/7 and you say x is the case and y is the number of balls... so it would be 7 balls per case

OpenStudy (jdoe0001):

hmmm you're referring to the Joules and Celsius slope, yes, that was 1/7

OpenStudy (anonymous):

o crap.. sorry i got confused

OpenStudy (jdoe0001):

but if the slope in this case were 1/7 on the cases and balls...yes, it'd be 1/7 ball per case =)

OpenStudy (jdoe0001):

kinda no easy to play tennis with 1/7 of a ball though

OpenStudy (anonymous):

xD

OpenStudy (anonymous):

what about number 10? i dont really understand what the question is asking

OpenStudy (anonymous):

sorry i mean 11

OpenStudy (jdoe0001):

well.. you know the equation from Joules and Celsius so to know how much it'd take to get 260 degrees.... .solve it like so the degrees are the OUTPUT so set y = 260 and solve for "x"

OpenStudy (anonymous):

i got 126.38 repeating for 10 but i meant 11

OpenStudy (jdoe0001):

a negative value of the function... means a negative Degree so the gold bar was 25 from the getgo y = 25 means 0 joules into it 24, 23, 22, 21, 20 ...... 3, 2, 1 , -1, -2 ,-3, -4? what do you think that means for the gold bar?

OpenStudy (anonymous):

its temperature decreases?

OpenStudy (jdoe0001):

well.... yes..... it's think about say... you're the gold bar, and you're sitting at the tv watching the weather forecast and the newscast say "well folks it was 25 degrees yesterday BUT today is going to be -4 degrees" how would you feel?

OpenStudy (anonymous):

shocked? there was a dramatic decrease in temperature from 1 day to another

OpenStudy (jdoe0001):

well... surely... besides that, you'd be wearing thicker clothes so you're really no "warm" anymore...you're getting "colder"

OpenStudy (anonymous):

ok so a negative value of h(t) means the gold bar is getting colder

OpenStudy (jdoe0001):

yeap

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