write the equation of a function h(t) that represents the amount of heat in joules required to heat the bar to a temp of t degrees Celsius
@jdoe0001 @Nnesha
hmm what did the table give you?
usually the Joules and Celsius made could just be used as an "x" and "y" table with each pair being a coordinate of the graph so you'd do the same as before to get the equation, pick 2 points, get their slope and then plug in the point-slope form
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hmmm well... the gold bar was 25 degrees warm from the getgo to raise it to 26 you'd just need 7Joules so would be more like \( \bf \begin{array}{ccllll} Joules&Celsius \\\hline\\\ x&y \\\hline\\ 7&26\\ {\color{red}{ 14}}&{\color{blue}{ 27}}\\ 21&28\\ {\color{red}{ 28}}&{\color{blue}{ 29}}\\ 35&30 \end{array} \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 14}}\quad ,&{\color{blue}{ 27}})\quad &({\color{red}{ 28}}\quad ,&{\color{blue}{ 29}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)
slope is 7 y=7x-168
o nevermind, you used joules as x not y give me a sec
keep in mind that Joules is the INPUT, and the Celsius is the OUTPUT
wait your graph is wrong
hmm.... where is it off?
x is 14 and y is 26 not x is 7
hmmm ok...... x = 14 means 2 Celsius or 7 + 7 Joules starting off at 25 degrees warm, the gold bar will go up to 27
o ok, i see. so it doesnt start with 7, 25 because nothings been heated its just 0,25
yeap
so slope is still 7
y=7x-175?
how do i put that in the h(t) thing?
hmm site is getting laggy
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 14}}\quad ,&{\color{blue}{ 27}})\quad &({\color{red}{ 28}}\quad ,&{\color{blue}{ 29}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ 29}}-{\color{blue}{ 27}}}{{\color{red}{ 28}}-{\color{red}{ 14}}}\implies ?\)
2/14 or 1/7
yeap thus \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 14}}\quad ,&{\color{blue}{ 27}})\quad &({\color{red}{ 28}}\quad ,&{\color{blue}{ 29}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{1}{7} \\ \quad \\ y-{\color{blue}{ 27}}={\color{green}{ \cfrac{1}{7}}}(x-{\color{red}{ 14}})\qquad \textit{plug in the values }\\ \qquad \uparrow\\ \textit{point-slope form} \)
it doesn't need it in any specific form... so I gather point-slope form is just as good
ok, what about #12?
he/she 's buying cases of balls, each case has 24 cans, each can 24 balls the INPUT here is how many cases? the OUTPUT is how many balls? well... in 1 case there are 24* 3 balls so there \(\large \begin{array}{rrrllll} cases&balls \\\hline\\ 1&24\cdot 3\to 72\\ 2&144\\ 3&288\\ 4&576\\ ...&... \end{array}\) pick any 2 points, get the "x" and "y" and get their slope and same as before plug in the point-slope form
woops he/she 's buying cases of balls, each case has 24 cans, each can 3 balls thus 24 * 3
slope is 72
y=72x?
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hmmm right my table is a bit off there.... but yes... that's correct should be \(\begin{array}{rrrllll} cases&balls \\\hline\\ 1&24\cdot 3\to 72\\ 2&144\\ 3&288\\ 4&360\\ ...&... \end{array}\) anyhow
yeap
so how would i graph that with no y-intercept
you forgot about our good fellow Mr Zero \(\large \begin{array}{llll} y=&{\color{brown}{ 72}}x&{\color{blue}{ +0}}\\ &\uparrow &\uparrow \\ &{\color{brown}{ slope}}&{\color{blue}{ y-intercept}} \end{array}\)
o ok :) what does the slope represent in the function? the number of cans in a case?
slope is a rate of change how much is "y" changing on every change in "x"
so.... in this case... "y" is how many balls in each "x" cases
that would mean there are 7 balls in each case :/
yes IF the slope were 7, yes
well if our slope is 1/7 and you say x is the case and y is the number of balls... so it would be 7 balls per case
hmmm you're referring to the Joules and Celsius slope, yes, that was 1/7
o crap.. sorry i got confused
but if the slope in this case were 1/7 on the cases and balls...yes, it'd be 1/7 ball per case =)
kinda no easy to play tennis with 1/7 of a ball though
xD
what about number 10? i dont really understand what the question is asking
sorry i mean 11
well.. you know the equation from Joules and Celsius so to know how much it'd take to get 260 degrees.... .solve it like so the degrees are the OUTPUT so set y = 260 and solve for "x"
i got 126.38 repeating for 10 but i meant 11
a negative value of the function... means a negative Degree so the gold bar was 25 from the getgo y = 25 means 0 joules into it 24, 23, 22, 21, 20 ...... 3, 2, 1 , -1, -2 ,-3, -4? what do you think that means for the gold bar?
its temperature decreases?
well.... yes..... it's think about say... you're the gold bar, and you're sitting at the tv watching the weather forecast and the newscast say "well folks it was 25 degrees yesterday BUT today is going to be -4 degrees" how would you feel?
shocked? there was a dramatic decrease in temperature from 1 day to another
well... surely... besides that, you'd be wearing thicker clothes so you're really no "warm" anymore...you're getting "colder"
ok so a negative value of h(t) means the gold bar is getting colder
yeap
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