Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (amtran_bus):

Integral question

OpenStudy (amtran_bus):

OpenStudy (amtran_bus):

@inkyvoyd

OpenStudy (amtran_bus):

I know the substitution formula and how to get U and DU, so on so fourth.

zepdrix (zepdrix):

So where we getting stuck? Let u equal the stuff up in the exponent. Ooo this one works out nicely I think!

zepdrix (zepdrix):

\[\LARGE\rm \int\limits t^{15}e^{-t^8}dt=\int\limits t^{8+7}e^{-t^8}dt\]\[\Large\rm =\int\limits t^8 e^{-t^8}\left(t^7~dt\right)\]If you break it up like this, it might be easier to plug in your substitution.

zepdrix (zepdrix):

\(\Large\rm u=-t^8\) \(\Large\rm du=-8\left(t^7~dt\right)\)Can you kinda see what's going on?

OpenStudy (amtran_bus):

Hmm yes I like how you broke it up.

OpenStudy (amtran_bus):

Well, I thought I was getting it. Just me, I was doing U=t^15 DU=15t^14 DV=e^-t8

zepdrix (zepdrix):

So you were trying to jump right into the `integrating by parts` before doing a substitution. See how that runs into trouble? Finding your V would be impossible without borrowing some of those t's from the U.

zepdrix (zepdrix):

Confused still senor bus? :U

OpenStudy (amtran_bus):

Oh goodness. It does help to read instructions! Forgive me zepdrix. Thanks for your patience and help! My AmTran is tired lol. Onward!

OpenStudy (amtran_bus):

So the substitution is basically breaking up the 15?

zepdrix (zepdrix):

I'll call it something else, not u, so there's no confusion that this has nothing to do with integration by parts. \[\Large\rm \color{orangered}{m=-t^8}\qquad\to\qquad \color{royalblue}{-m=t^8}\]\[\Large\rm \color{green}{-\frac{1}{8}dm=\left(t^7~dt\right)}\]Yah, we're breaking up the 15, and applying a substitution before even assigning any parts.\[\Large\rm =\int\limits\limits \color{orangered}{t^8} e^{\color{royalblue}{-t^8}}\color{green}{\left(t^7~dt\right)}\]

zepdrix (zepdrix):

Bahh I got the orange and blue backwards.. my bad :P

OpenStudy (amtran_bus):

Thats fine! The m makes sense!

zepdrix (zepdrix):

\[\Large\rm =\frac{1}{8}\int\limits m e^m~dm\]So before applying our parts, we have ummm something like this, yes?

zepdrix (zepdrix):

And I'll bet you can handle the parts from there c: Shouldn't be too bad.

OpenStudy (amtran_bus):

I'll try!

OpenStudy (amtran_bus):

This gives a foundation to work with.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!