Question

Rationalize the denominator.

6/√(5 + √11)

Answer 1

hmm

Answer 2

my algebra is failing me on what to do after i multiply the bottom by rt 5

Answer 3

i mean this is for a pre-cal review I'm doing

Answer 4

yah but this concept is from alg 2

Answer 5

I tried to multiply the bottom by sqrt 5-sqrt 11 but it didn't work

Answer 6

too many square roots

Answer 7

actually it is not clear what you wrote

Answer 8

the answer is sqrt 11 - sqrt 5 but i need to know how to get the answer

Answer 9

\[\frac{6}{\sqrt5+\sqrt{11}}\]?

Answer 10

yes like that

Answer 11

tats not what u wrote before

Answer 12

multiply by the conjugate, you get it right away

Answer 13

i tried :(

would the conjugate be √5 - √11

Answer 14

\[\frac{6}{\sqrt{5}+\sqrt{11}}\times \frac{\sqrt5-\sqrt{11}}{\sqrt{5}-\sqrt{11}}\]
denominator is \(5-11=-6\) so you get
\[\frac{6(\sqrt5-\sqrt{11})}{-6}\]

Answer 15

then cancel
you be done

Answer 16

AH i forgot about conjugate

Answer 17

its oposite the sign. thank you

Answer 18

am i canceling 6 and -6?

Answer 19

\[\frac{\cancel6(\sqrt5-\sqrt{11})}{-\cancel6}=-(\sqrt5-\sqrt{11})=\sqrt11-\sqrt5\]\]

Answer 20

yes you are cancelling

Answer 21

OHH i got it now thank you so much!

Answer 22

yw