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Calculus1 15 Online
OpenStudy (anonymous):

find the lengths of all sides and the measures of all angles

OpenStudy (anonymous):

|dw:1408678333497:dw|

OpenStudy (anonymous):

and |dw:1408678375053:dw|

OpenStudy (tkhunny):

You should recognize both the 45-45-90 Right Triangle and the 30-60-90 Right Triangle.

OpenStudy (anonymous):

thank you ! how do you use trigonometry to find the sides ?

OpenStudy (tkhunny):

You don't. 1) The lengths of the sides are c. 2) The lengths of the sides are x ad xsqrt(3)

OpenStudy (anonymous):

it only gives you 2 out of the 3 sides for both triangles

OpenStudy (kc_kennylau):

Use the pythagoras' theorem.

OpenStudy (anonymous):

you can't use it in this instance . that's only for numbers not variables

OpenStudy (kc_kennylau):

Yes you can, it does not matter if they are variables

OpenStudy (tkhunny):

That's right. 45-45-90 right triangle has lengths c, c, and c*sqrt(2) You can use the Pythagorean Theorem if you would like, but these two special cases should be in the tip of your tongue. There is no difference between numbers and variables. Variables ARE numbers.

OpenStudy (anonymous):

okay .. then how would you get it for the x and 2x triangle ? since its a 30-60-90

OpenStudy (kc_kennylau):

Have you learnt the value of \(\cos60^\circ\)?

OpenStudy (tkhunny):

Like I said in the beginning, you should KNOW these two special cases. 30-60-90 Hypontenuse 2x Short side x long side x*sqrt(3) You can demonstrate with teh Pythagorean Theorem \(\sqrt{(2x)^{2} - x^{2}} = \sqrt{4x^{2} - x^{2}} = \sqrt{3x^{2}} = x\sqrt{3}\)

OpenStudy (anonymous):

OOOH okay i understand now . i haven't done math all summer and im trying to work on my review packet

OpenStudy (tkhunny):

Show me the 45-45-90.

OpenStudy (anonymous):

|dw:1408680687223:dw|

OpenStudy (tkhunny):

Well, there you go!

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