Solution to the compound inequality -8 < 2x-4 <2 the first < is underlined.
Have you considered dividing by 2 and adding 2 (in that order)?
Or adding 4 then divide by 2, the more obvious way
you got this?
I dare you to defend your position that one or the other is "more obvious".
No, not really. I got -4 < -4 after I divided by two. I think its wrong.
Why did your inequality change? There used to be two relationships. You lost one. -8 < 2x-4 <2 Divide by 2 -4 < x-2 < 1 See, still 2 relationships. OR add 4 -4 < 2x < 6 Still 2 relationships.
Okay, so what do you do from there?
@tkhunny
You're almost done. Both methods have been explained. Finish one of them.
Should I add four to each side?
I don't know. I'm not sure where you are starting. Are you back at the beginning? Careful with the phrase "each side". You have three "sides".
@tkhunny Well right now I have -4<2x<6 do I add the -4 to the first and last side?
\(-4 \le 2x < 6\) You want x by itself. Why would you do anything with the 4? That gets you nowhere. Try dividing by 2.
so now its -2 < x <3
@tkhunny
?? You do need to be able to see when you are done. Is x "solved for"? You're done.
I need help on some other problems to, would you mind helping me? I was just checking to make sure I was correct, btw
@tkhunny
-2≤x<3 is the answer
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