Mathematics
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OpenStudy (anonymous):
fine the difference quotient f(3+h)-f(3) and simplify if f(x) is x^2-2x+9
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OpenStudy (anonymous):
divided by h
OpenStudy (anonymous):
did you find \(f(3)\) ? you need that first
OpenStudy (anonymous):
no im having dificulties
OpenStudy (anonymous):
it is a direct computation
if you cannot find it, the other part will make less than no sense to you
OpenStudy (anonymous):
do you just plug 3 into x^2-2x+9?
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OpenStudy (kc_kennylau):
Yep
OpenStudy (anonymous):
\[f(x) = x^2-2x+9\\
f(\clubsuit)=\clubsuit^2-2\clubsuit +9\\
f(3)=3^2-2\times 3+9\]\]
OpenStudy (anonymous):
let me know when you get \(12\)
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
next you need to do something harder
find \(f(3+h)\)
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OpenStudy (anonymous):
ok i got 12
OpenStudy (anonymous):
\[f(\clubsuit)=\clubsuit^2-2\clubsuit +9\\\] where you see a \(\clubsuit\) replace it by \(3+h\)
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
let me know what you get
OpenStudy (anonymous):
im not sure if its right i got h^2+4h+12
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OpenStudy (anonymous):
think so, let me check
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
ok now subtract
\[f(3+h)-f(3)=h^2+4x+12-12=?\]
OpenStudy (xapproachesinfinity):
Good^_^
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
i got h^2+4h
OpenStudy (anonymous):
ok good
last step
divide both terms by \(h\)
OpenStudy (anonymous):
h+4 :D?
OpenStudy (anonymous):
do you always find f(whatever number) and then the rest
OpenStudy (anonymous):
yes you are done
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OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
yw
hope it was more or less clear