Question

Motor cyclist moving with a velocity of 72 km/hr on a flat road takes a turn on the road at a point where radius of curvature of the road is 20 metres. the acceleration due to gravity is \(\sf 10 m/s^2\). In order to avoid skidding, he must not bend with respect to the vertical plane by an angle greater than

Answer 1

@Abmon98

Answer 2

http://books.google.com.qa/books?id=M-gDAAAAMBAJ&pg=PA993&lpg=PA993&dq=In+order+to+avoid+skidding,+he+must+not+bend+with+respect+to+the+vertical+plane+by+an+angle+greater+than&source=bl&ots=qol0aBmB0l&sig=1mPnQgGUamwFj_OCFFj8ZYCtiIc&hl=ar&sa=X&ei=4cT2U9CtN5XYaoHrgdgP&redir_esc=y#v=onepage&q=In%20order%20to%20avoid%20skidding%2C%20he%20must%20not%20bend%20with%20respect%20to%20the%20vertical%20plane%20by%20an%20angle%20greater%20than&f=false

Answer 3

yeah i just figured it out by myself !
:)

Answer 4

\[V=72km/hr \]\[V=72*1000/60*60 \]\[v=20m/s \] m/s
\[\tan \theta=v^2/rg\]
\[\tan \theta=20*20/20*10\]
if you cannot open the link, good to hear that :D

Answer 5

yes, we will have to consider the optimum condition and take frictional force as zero.

Answer 6

Thank you for your time though :)

Answer 7

my pleasure :D

Answer 8

Here all the centripetal force is due to the sin component of normal force.