Can someone please help me! I will fan+medal Find the sum of the first six terms of the geometric sequence for which a2=0.7 and a3=0.49
what is the value of r?
0.7
so what is the value of a1, a4, a5, a6?
well we don't even need all of the terms
a1=0.1 a4=3.43 a5=24.01 a6=168.07
you're multiplying by 0.7 not 7. the numbers should be getting smaller after a3. im trying to find that one formula
but to get to 0.7 you must multiply 0.1 times 7 and to get to 0.49 you must multiply 0.7 to 0.7
if you see 0.7 times 0.7=0.49
ok I found it. \(\huge S_n=a_1(\frac{{1-r}^n}{1-r})\)
ok first thing's first, to get a1, we have to divide a2 by 0.7 because we're working backwards.
mhmm
thats 0.1
if a1 = 0.1 and the ratio = 0.7 a2 would be 0.07 if a1 = 1 and the ratio = 0.7 a2 would be 0.7
oh okay
For reference, 0.7/0.7 = \(a_1\) = 1
yeah makes sense
so where were we \(\huge S_n=a_1(\frac{{1-r}^n}{1-r})\) \(\huge S_n=1(\frac{{1-0.7}^6}{1-0.7})=\frac{0.3^6}{0.3}\)
umm i got 0.00243
same I don't know if that makes sense
1+0.7+0.49+... should be at least 1
but the way i did it before, the way that you thought was wrong i got 196.8
That's definitely wrong. 1, 0.7, 0.49, 0.343, 0.2401, 0.16807 is the actual series assuming r = 0.7
hmm so lost
here, if \(\large a_2=0.7 \) \(\large a_3=0.49 \) That means the common ratio is 0.7. That also means that \(\large a_1=1\) and \(\large a_4=0.343\)
so whats the answer?
1 + 0.7 + 0.49 + 0.343 + 0.2401 + 0.16807
I'll try it again with one of the formulas in a sec
oh wow I'm an absolute idiot
?
\(\huge S_n=a_1(\frac{{1-(r}^n)}{1-r})\)\(\large r=0.7, n =6\) \[\large S_n=(\frac{{1-(r}^n)}{1-r})=(\frac{{1-(0.7}^6)}{1-0.7})=\frac{1-0.117649}{0.3}= \frac{0.882351}{0.3}=2.94117\]
2.94117
thats the final answer?
yeah. I did the math too, google agrees 1 + 0.7 + 0.49 + 0.343 + 0.2401 + 0.16807 =2.94117
thanks so much!
sorry about getting caught up with something as stupid as an arithmetic mistake
its geometric :) and its okay
I can't tell if that's a joke or not :p I meant the fact that I subtracted before raising the power. PEDMAS
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