d
@chris00
9(9-8k)=2x+3? 9(-9+8k)=2x+3?
why
@KlOwNlOvE
| | are just like parenthesis only you have to find the reciprocal to find 2 solutions so you get a + absolute value then - absolute value
So its now just 9 -9 (-) 8x = 2x +3
That is not the exact meaning. It goes like this: | x | helps us calculate the absolute value of any number. Because, if x is negative [-1,-2,-3...] then to make it positive. !x| = -x [because -(-1), -(-2), -(-3)... = 1,2,3....] Now if x is positive, then |x| = x So there are two solutions to |x| = +x [when x is positive], -x {when x is negative] So two solve your question, we take two equations, where we change the sign on |9-8x| because when 9-8x is negative, |9-8x| = -(9-8x) when 9-8x is positive |9-8x| = (9-8x) and then we incorporate both possibilities in our equation to find the values of x for the conditions. Getting this? :)
1 second
no im sorry I dont understand. im super tired its 2AM here.
square both sides, the absolute bars go away
Can you show me what that looks like after squareD?
9|9 - 8x| =2x +3 (9(9-8x))^2 = (2x+3)^2 simplify
If we do that, we'll get more solutions. Extraneous!
yes we want extraneous solutions to check right
if we approach it directly, we won't get any extraneous solutions and the question would be pointless :P
do you multiply those two nines ?
you may : 9|9 - 8x| =2x +3 (9(9-8x))^2 = (2x+3)^2 (81-72x)^2 = (2x+3)^2
can you expand it further using (a+b)^2 formula ? you will get a quadratic which you can factor/solve
what is "^"
squared? so 9 squared?
that means exponent
Ganeshie I dont know if you got my message, but yeh, I do.
Okay, it seems the squaring method is getting tedious, lets leave it here.
work it using @KlOwNlOvE first method, it looks good
my brain is everywhere. I just want to give up but I cant. I just dont understand. The most frusturating part is that I was doing these yesterday fine but I cant think straight. for some reason I want to add the 8x to get it with the 2x, but i know tahts not right
9|9 - 8x| =2x +3 ``` 9(9-8x) = 2x+3 or 9(9-8x) = -(2x+3) 81-72x = 2x + 3 81-72x = -2x - 3 78 = 74x 84 = 70x 39/37 = x 6/5 = x ``` So your two solutions are : x = 39/37 and x = 6/5
plug them in the original absolute value equation and see if they satisfy
where did you get 39/37 tho
`78/74` simplifies to `39/37` after cancelling `2` in numerator and denominator
oh, thank you alot. you were great help.
\[\large \dfrac{78}{74} = \dfrac{2*39}{2*37} = \dfrac{39}{37}\]
that makes alot of sense now.
good, you need to plugin the solutions in original equations and make sure they satisfy
9|9 - 8x| =2x +3 plugin x = 39/37 and simplify both sides, you should get same number on both sides
okay
they both work
Here, more steps : 9|9 - 8x| =2x +3 ``` 9(9-8x) = 2x+3 or 9(9-8x) = -(2x+3) 81-72x = 2x + 3 81-72x = -2x - 3 78 = 74x 84 = 70x 78/74 = x 84/70 = x 39/37 = x 6/5 = x ``` So your two solutions are : x = 39/37 and x = 6/5
yes they both work ! so they're not extraneous
they are good working solutions, NOT extranoise solutions :)
thank you. alot. must. sleep.
good night! have horrible math dreams :P
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