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Mathematics 19 Online
OpenStudy (anonymous):

15a^2-6a÷5a-2

OpenStudy (joannablackwelder):

Is that \[\frac{ 15z ^{2}-6a }{ 5a-2 }\]?

OpenStudy (joannablackwelder):

Those should all be a's.

OpenStudy (anonymous):

yup

OpenStudy (joannablackwelder):

Ok. :) Can you factor anything out of the numerator?

OpenStudy (anonymous):

how :(

OpenStudy (anonymous):

can you do it for me thats how the question is

OpenStudy (joannablackwelder):

By finding common factors.

OpenStudy (joannablackwelder):

\[15a ^{2}-6a\] Do you see that 15 and 6 are divisible by 3?

OpenStudy (anonymous):

yup :)

OpenStudy (anonymous):

go ahead pliz :)

OpenStudy (joannablackwelder):

Cool. :) That means you can factor out a 3.

OpenStudy (anonymous):

im listening lol :)

OpenStudy (joannablackwelder):

That looks like this \[3(5a ^{2}-2a)\]

OpenStudy (anonymous):

aha

OpenStudy (joannablackwelder):

It is like reverse distributing.

OpenStudy (joannablackwelder):

Do you see any other common factors?

OpenStudy (anonymous):

no , where ?

OpenStudy (joannablackwelder):

In the numerator still.

OpenStudy (joannablackwelder):

Do you see that there are a's in both terms?

OpenStudy (anonymous):

the a's huh

OpenStudy (joannablackwelder):

Right.

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

got ya

OpenStudy (joannablackwelder):

You can factor out 1 a.

OpenStudy (anonymous):

right

OpenStudy (joannablackwelder):

So, can you show me what that looks like?

OpenStudy (anonymous):

3(5a-2)

OpenStudy (joannablackwelder):

Very close. The a you factored out goes with the 3.

OpenStudy (joannablackwelder):

3a(5a-2)

OpenStudy (anonymous):

got ya

OpenStudy (joannablackwelder):

:) Let's put that back in the original fraction.\[\frac{ 3a(5a-2) }{ 5a-2 }\]

OpenStudy (joannablackwelder):

You can cancel out common factors in the numerator and denominator.

OpenStudy (anonymous):

3a ?

OpenStudy (joannablackwelder):

Perfect! :)

OpenStudy (anonymous):

is that the answer :o

OpenStudy (joannablackwelder):

You got it!

OpenStudy (anonymous):

wow

OpenStudy (anonymous):

do i have to pay ya for this :)

OpenStudy (anonymous):

u better than all my teachers

OpenStudy (joannablackwelder):

Haha, no charge :)

OpenStudy (joannablackwelder):

Glad I can help!

OpenStudy (anonymous):

im not lying bruh :)

OpenStudy (joannablackwelder):

But I do private tutoring if you are interested.

OpenStudy (anonymous):

u a nice person :)

OpenStudy (anonymous):

where u from thou ?

OpenStudy (joannablackwelder):

I'm from America.

OpenStudy (anonymous):

i have some other questions before i sleep, hope u will do it for me

OpenStudy (joannablackwelder):

I can try.

OpenStudy (anonymous):

just 3 of em not much :) u smart thou

OpenStudy (joannablackwelder):

Ok. :)

OpenStudy (anonymous):

first i thought u were a computer lol :)

OpenStudy (joannablackwelder):

Thanks.

OpenStudy (joannablackwelder):

Haha! Really?!

OpenStudy (anonymous):

yup :)

OpenStudy (anonymous):

im glad u human :)

OpenStudy (anonymous):

supper human :)

OpenStudy (joannablackwelder):

Haha, I'm glad I'm not a computer too!

OpenStudy (anonymous):

ok here

OpenStudy (anonymous):

64a^4÷32a^10+24a^4

OpenStudy (anonymous):

this one kinder clear , but show me first :)

OpenStudy (joannablackwelder):

Ok. This time we need to factor the denominator.

OpenStudy (joannablackwelder):

Common factors of the denominator: 8a^4

OpenStudy (anonymous):

wait , come again pliz

OpenStudy (joannablackwelder):

32a^10+24a^4 This is what we need to factor.

OpenStudy (joannablackwelder):

So we need to factor out common factors.

OpenStudy (anonymous):

ok :/

OpenStudy (joannablackwelder):

You can always factor out the least number of the variable in each term.

OpenStudy (joannablackwelder):

So, you can factor out a^4.

OpenStudy (anonymous):

which is 8 ??

OpenStudy (joannablackwelder):

No, that is the a^4 part.

OpenStudy (anonymous):

oh ok :)

OpenStudy (joannablackwelder):

:)

OpenStudy (joannablackwelder):

Let's factor out a^4 first.

OpenStudy (joannablackwelder):

a^4(32a^6+24)

OpenStudy (joannablackwelder):

Making sense still?

OpenStudy (anonymous):

yeah

OpenStudy (joannablackwelder):

Great!

OpenStudy (joannablackwelder):

That is all the a's we can take out. So, now we need to figure out what numbers we can take out.

OpenStudy (joannablackwelder):

32=2*2*2*2*2

OpenStudy (anonymous):

right

OpenStudy (joannablackwelder):

And 24=2*2*2*3

OpenStudy (joannablackwelder):

So, what is common is 2*2*2

OpenStudy (joannablackwelder):

which is 8.

OpenStudy (anonymous):

@skullpatrol is a allrounder

OpenStudy (joannablackwelder):

Still with me?

OpenStudy (anonymous):

yup

OpenStudy (joannablackwelder):

Yay! :)

OpenStudy (anonymous):

yeah pliz :)

OpenStudy (anonymous):

u dea ??

OpenStudy (joannablackwelder):

So, we can factor out an 8 too. 8a^4(4a^6+3) (Short technical difficulty)

OpenStudy (joannablackwelder):

Make sense?

OpenStudy (anonymous):

aha

OpenStudy (anonymous):

yeah

OpenStudy (joannablackwelder):

Cool. So now we can put the fraction back together.

OpenStudy (joannablackwelder):

\[\frac{ 64a ^{4} }{ 8a ^{4} (4a ^{6}+3)}\]

OpenStudy (joannablackwelder):

And cancel out any common factors from the top and bottom.

OpenStudy (joannablackwelder):

See any?

OpenStudy (anonymous):

yeah

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