How many grams of magnesium metal will react completely with 6.3 liters of 4.5 M HCl? Show all of the work needed to solve this problem.

Mg (s) + 2 HCl (aq) yields MgCl2 (aq) + H2 (g)

Question

How many grams of magnesium metal will react completely with 6.3 liters of 4.5 M HCl? Show all of the work needed to solve this problem.

Mg (s) + 2 HCl (aq) yields MgCl2 (aq) + H2 (g)

anonymous · Answer

Any help would be great. I have no idea what's going on in chemistry.

nathalyn · Answer

moles HCl = 4.8 x 5 = 24 
moles Mg = 24/2 = 12 
mass Mg = 12 mol x 24.305 g/mol= 292 g

anonymous · Answer

Would you be able to describe exactly how to do this?

nathalyn · Answer

well I wish but no, but what I gave you that's the answer

anonymous · Answer

Okay. Well, thanks anyway.

nathalyn · Answer

welcome

anonymous · Answer

moles= volume(litres) X molarity(Concentration)
         =6.3 X 4.5
         = 28.35 moles
 mole ratio Mg:HCl  =1:2
 
if 2= 28.35 moles
   1= ?

$$\frac{ 1\times28.35 }{ 2 }$$

 Mg has 14.175 moles

mass= moles X RAM
        = 14.175 X23
         
        =326.025g

anonymous · Answer

different answer? @NathalyN what's wrong with my answer then?