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domain of sqrt(x^2-3) / sqrt(4-x)
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I found sqrt(3)<=x<4
How did you find that ?
x^2-3>=0 and 4-x>0
Yeah, so from the first inequality, what would you get ?
x greater or equal to sqrt of 3
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yeah your answer is correct.
I was confused about it at first because x²>=3 means x>=sqrt(3) or x<=-sqrt(3)
i think its ok for x less than neg. Sqrt of 3, if you pulg it in..
both numerator and denominator are defined
Yeah that's was I thought, so the domaine would be \[]-\infty,-\sqrt{3} ] \cup [\sqrt{3},4[\]
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ok, thanks for your help
Welcome ! p.s: you can see it here : https://www.desmos.com/calculator/z0lnkkgwnj
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